A horizontal alignment consists of two tangent lin connected by a horizontal curve, as shown in figures below. PC is located at sta. 10+00.00. The overall length of the horizontal curve is 400 feet and an 8% superelevation needs to be designed for the curve. The superelevation runoff length is chosen to be 240 feet. The normal cross-section is also shown in the figure. Both left and right sections have 2% slopes for drainage. On the circular curve, the left section is on the external side and therefore needs to be raised while the right section is on the internal side and should be lowered. The rotation axis is on the center line of the highway, which is shown as a black dot in the figure.

A horizontal alignment consists of two tangent lin connected by a horizontal curve, as shown in figures below. PC is located at sta. 10+00.00. The overall length of the horizontal curve is 400 feet and an 8% superelevation needs to be designed for the curve. The superelevation runoff length is chosen to be 240 feet. The normal cross-section is also shown in the figure. Both left and right sections have 2% slopes for drainage. On the circular curve, the left section is on the external side and therefore needs to be raised while the right section is on the internal side and should be lowered. The rotation axis is on the center line of the highway, which is shown as a black dot in the figure.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Two straight alignment intersect at a chainage of 4687.50 m with a deflection angle of 43°. A circular curve of radius 380 m with transition carves of 50 m each on the two ends. Compute the data for setting out the curve with page at 20 m for circular curve and 10 m for transition curve.
Vertical alignment: Four intersecting tangents for a proposed alignment of a roadway has the following data: AB= +2.5%, 105. 34m BC = -3.5%, 125.67m CD = +5.5%, 156.78m DE = -6.5%, 235.67m Note: The distances above are horizontal distance 5. Determine the difference in elevation between points B and D. a) 4.89m b) 5.23m c) 4.18m 6. What is the difference in elevation between points A and E. a) 9.45m b) 8.46m c) 7.56m d) 3.24m d) 9.20m
Pls solve correct and stepwise
Sample Problem #1: The back tangent with grade of +3.4% and forward tangent with grade of -4.8% intersects at station 14 + 750 and elevation 76.30m. The two tangents are connected by a 320m parabolic curve. A. Find the location of the highest point from PC. B. Compute the stationing of the highest point of the curve. C. Determine the elevation of the highest point.
Given the proposed longitudinal profile of the centerline of a rural two-lane highway as follows: PVLu STN 10+0) PVL: Elev. 100 ft G-2% Ge0% L=? Ly=? a) Calculate the required minimum design lengths (to meet the SSD requirements) of the three back-to-back vertical curves on this section of the roadway to accommodate a continuous design speed of 50 mph.
If any charts or graphs where use please Imsert below and explain how it’s used
Please don't Reject it. if you don't know , leave it.
Station TS (x+xxX.Xxx) Station SC (x+xXX.XXx)
The length of curve at side of PC is 50 while on the PT is 60 m. A sewer line with its top having an elevation of 107.4 is found at station 6+800. A parabolic curve is to be constructed having a back tangent of 5% and forward tangent of -8%, with PC stationed at 6+780 having an elevation of 110 m. Determine the height of fill from sewer line line.
10 please give the correct ans and the solution
A two-lane highway (one 3.6 m lane in each direction) goes from normal crown with 2% cross-slopes to 10% superelevation by means of a spiral transition curve. Determine the minimum length of the transition if the difference in grade between the centerline and edge of traveled way is limited to1:200.Round up to the next largest 20m interval.(b) Draw the superelevation diagram for the transition described in part a ,The station of the TS is 160+00