A homogeneous disk (lom = 9.00 102 Kgm²) with the radius R = 30 cm can rotate on a horizontal plane an axis passing through its centre.A torquer = 2.00 Nm is applied to the axis due to friction. Two masses m=200 g are placed on the disk at a distance R from the centre. An inextensible robe is wounded horizontally around the disc. The rope then passes through a pulley and is attached to a mass M. At the initial time the system is at rest and the mass M starts to fall down. Knowing that the tension of the rope during the motion is T-9.00 N compute: a) The value of the suspended mass M; b) The angular velocity of the disk after the mass M has descended by 24.3cm.
A homogeneous disk (lom = 9.00 102 Kgm²) with the radius R = 30 cm can rotate on a horizontal plane an axis passing through its centre.A torquer = 2.00 Nm is applied to the axis due to friction. Two masses m=200 g are placed on the disk at a distance R from the centre. An inextensible robe is wounded horizontally around the disc. The rope then passes through a pulley and is attached to a mass M. At the initial time the system is at rest and the mass M starts to fall down. Knowing that the tension of the rope during the motion is T-9.00 N compute: a) The value of the suspended mass M; b) The angular velocity of the disk after the mass M has descended by 24.3cm.
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Step 1: Given Information
VIEWStep 2: Calculating Moment of Inertia of the Disc Mass System
VIEWStep 3: Calculating the net torque acting on the disc
VIEWStep 4: Angular acceleration of the disc
VIEWStep 5: Acceleration of the suspended mass (or) Tangential aceleration of the disc
VIEWStep 6: Part a - Finding mass M
VIEWStep 7: Part b - Angular velocity of the disc
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