A HOMEWRK-1: The average cross-sectional area of leg 3 cm² and all of body weight 700 N supported of this leg, and the amount of shorting (AL) = 0.15 mm find the length of this leg in meter if you know that young's modulus of the bone is 1.8 * 1010 N/m². L = 1.157 m ANSWER A-3x F-100
A HOMEWRK-1: The average cross-sectional area of leg 3 cm² and all of body weight 700 N supported of this leg, and the amount of shorting (AL) = 0.15 mm find the length of this leg in meter if you know that young's modulus of the bone is 1.8 * 1010 N/m². L = 1.157 m ANSWER A-3x F-100
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HOMEWRK-1: The average cross-sectional area of leg 3 cm² and all of body weight 700
N supported of this leg, and the amount of shorting (AL) = 0.15 mm find the length of
this leg in meter if you know that young's modulus of the bone is 1.8 * 1010 N/m².
L = 1.157 m
ANSWER
واحد
ANSWER
ull
HOMEWRK-2: A leg of 1.0 M in length, and an average cross-sectional of 4 cm²
determine the amount of shortening (AL) when all of the body weight supported on this
leg, young's modulus of the bone is 1.8 * 1010 N/m².
AL= 0.6 mm
L?
A--3X1=4
F: 100
bbots
y-181110
16
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