A history book is lying on top of a physics book on a desk, as shown below; a free-body diagram is also shown. The history and physics books weigh 26 N and 27 N, respectively. Identify each force on each book with a double subscript notation (for instance, the contact force of the history book pressing against physics book can be described as Fn), and determine the value of each of these forces (in N), explaining the process used. (Express your answers in vector form. For the free-body diagram, assume the +x-direction is to the right and the +y-direction is up along the page.) Desk History book Physics book HISTORY Fdp PHYSICS "ph Fnp Fen N ph F = eh N Fdp

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each book with a double subscript notation (for instance, the contact force of the history book pressing against physics book can be described as Fon), and determine the value of each of these forces
(in N), explaining the process used. (Express your answers in vector form. For the free-body diagram, assume the +x-direction is to the right and the +y-direction is up along the page.)
A history book is lying on top of a physics book on a desk, as shown below; a free-body diagram is also shown. The history and physics books weigh 26 N and 27 N, respectively. Identify each force on
Desk
History book
Physics book
HISTORY
PHYSICS
ph
Fnp
Fep
Teh
Fph
N
N
eh
=
dp
N
Fep
%D
hp
Explain the process used.
II
Transcribed Image Text:each book with a double subscript notation (for instance, the contact force of the history book pressing against physics book can be described as Fon), and determine the value of each of these forces (in N), explaining the process used. (Express your answers in vector form. For the free-body diagram, assume the +x-direction is to the right and the +y-direction is up along the page.) A history book is lying on top of a physics book on a desk, as shown below; a free-body diagram is also shown. The history and physics books weigh 26 N and 27 N, respectively. Identify each force on Desk History book Physics book HISTORY PHYSICS ph Fnp Fep Teh Fph N N eh = dp N Fep %D hp Explain the process used. II
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