A helicopter rises vertically and t seconds after leaving the ground its velocity is given in feet per second by v(t) = 4t+ 216 (t+6)²* Which expression is equal to how far above the ground the helicopter will be after 6 seconds? 2. v(1)+v(2) + 6 3. 216 dt (t + 6)2 d. √ 4t+ 6 √° 4t 4. v(6) - v(0) 5. v'(6) 4t+ +v(6) 216 (t+6)² dt

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