A heavy crate is dragged 70 feet along a level floor. Find the work done if a force of 20 pounds at an angle of 32° is used. Round your answer to the nearest tenth. 989.3 ft-lb 874.8 ft-lb 741.9 ft-lb 1,187.3 ft-lb E

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Author:James Stewart
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Chapter1: Functions And Models
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### Work Done by a Force: Educational Example

**Problem Statement:**
A heavy crate is dragged 70 feet along a level floor. Find the work done if a force of 20 pounds at an angle of 32° is used. Round your answer to the nearest tenth.

**Options:**
1. 989.3 ft·lb
2. 874.8 ft·lb
3. 741.9 ft·lb
4. 1,187.3 ft·lb

**Explanation:**
To solve this problem, we need to calculate the work done using the formula:

\[ \text{Work} = F \cdot d \cdot \cos(\theta) \]

Where:
- \( F \) is the force applied (20 pounds)
- \( d \) is the distance over which the force is applied (70 feet)
- \( \theta \) is the angle of the force with respect to the horizontal (32°)
- \( \cos \) is the cosine function, which can be calculated using a calculator.

### Step-by-Step Calculation:

1. **Calculate \( \cos(32^\circ) \):**

   \[
   \cos(32^\circ) \approx 0.848
   \]

2. **Substitute the known values into the work formula:**

   \[
   \text{Work} = 20 \, \text{lb} \cdot 70 \, \text{ft} \cdot 0.848
   \]

3. **Compute the product:**

   \[
   \text{Work} \approx 20 \cdot 70 \cdot 0.848 = 1,187.2 \, \text{ft}\cdot\text{lb}
   \]

4. **Round the result to the nearest tenth:**

   \[
   \text{Work} \approx 1,187.2 \, \text{ft}\cdot\text{lb}
   \]

   Rounded to the nearest tenth, the work done is:

   \[
   \boxed{1,187.3 \, \text{ft}\cdot\text{lb}}
   \]

**Correct Answer:**
4. 1,187.3 ft·lb
Transcribed Image Text:### Work Done by a Force: Educational Example **Problem Statement:** A heavy crate is dragged 70 feet along a level floor. Find the work done if a force of 20 pounds at an angle of 32° is used. Round your answer to the nearest tenth. **Options:** 1. 989.3 ft·lb 2. 874.8 ft·lb 3. 741.9 ft·lb 4. 1,187.3 ft·lb **Explanation:** To solve this problem, we need to calculate the work done using the formula: \[ \text{Work} = F \cdot d \cdot \cos(\theta) \] Where: - \( F \) is the force applied (20 pounds) - \( d \) is the distance over which the force is applied (70 feet) - \( \theta \) is the angle of the force with respect to the horizontal (32°) - \( \cos \) is the cosine function, which can be calculated using a calculator. ### Step-by-Step Calculation: 1. **Calculate \( \cos(32^\circ) \):** \[ \cos(32^\circ) \approx 0.848 \] 2. **Substitute the known values into the work formula:** \[ \text{Work} = 20 \, \text{lb} \cdot 70 \, \text{ft} \cdot 0.848 \] 3. **Compute the product:** \[ \text{Work} \approx 20 \cdot 70 \cdot 0.848 = 1,187.2 \, \text{ft}\cdot\text{lb} \] 4. **Round the result to the nearest tenth:** \[ \text{Work} \approx 1,187.2 \, \text{ft}\cdot\text{lb} \] Rounded to the nearest tenth, the work done is: \[ \boxed{1,187.3 \, \text{ft}\cdot\text{lb}} \] **Correct Answer:** 4. 1,187.3 ft·lb
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