A heat engine running backward is called a refrigerator if its purpose is to extract heat from a cold reservoir. The same engine running backward is called a heat pump if its purpose is to exhaust warm air into the hot reservoir. Heat pumps are widely used for home heating. You can think of a heat pump as a refrigerator that is cooling the already cold outdoors and, with its exhaust heat QH, warming the indoors. Perhaps this seems a little silly, but consider the following. Electricity can be directly used to heat a home by passing an electric current through a heating coil. This is a direct, 100% conversion of work to heat. That is, 19.0 kW of electric power (generated by doing work at the rate 19.0 kJ/s at the power plant) produces heat energy inside the home at a rate of 19.0 kJ/s. Suppose that the neighbor's home has a heat pump with a coefficient of performance of 3.00, a realistic value. NOTE: With a refrigerator, "what you get" is heat removed. But with a heat pump, "what you get" is heat delivered. So the coefficient of performance of a heat pump is K = QH/Win. An average price for electricity is about 40 MJ per dollar. A furnace or heat pump will run typically 250 hours per month during the winter. How much electric power (in kW) does the heat pump use to deliver 19.0 kJ/s of heat energy to the house? Express your answer in kilowatts. ► View Available Hint(s) Win = Submit Part B Cost₁= ——| ΑΣΦ Submit What does one month's heating cost in the home with a 19.0 kW electric heater? Express your answer in dollars. ► View Available Hint(s) ? ΠΙΑΣΦ kW $

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
icon
Related questions
Question
A heat engine running backward is called a refrigerator if its
purpose is to extract heat from a cold reservoir. The same
engine running backward is called a heat pump if its
purpose is to exhaust warm air into the hot reservoir. Heat
pumps are widely used for home heating. You can think of
a heat pump as a refrigerator that is cooling the already
cold outdoors and, with its exhaust heat QH, warming the
indoors. Perhaps this seems a little silly, but consider the
following. Electricity can be directly used to heat a home by
passing an electric current through a heating coil. This is a
direct, 100% conversion of work to heat. That is, 19.0 kW
of electric power (generated by doing work at the rate
19.0 kJ/s at the power plant) produces heat energy inside
the home at a rate of 19.0 kJ/s. Suppose that the
neighbor's home has a heat pump with a coefficient of
performance of 3.00, a realistic value. NOTE: With a
refrigerator, "what you get" is heat removed. But with a
heat pump, "what you get" is heat delivered. So the
coefficient of performance of a heat pump is
K = QH/Win. An average price for electricity is about
40 MJ per dollar. A furnace or heat pump will run typically
250 hours per month during the winter.
How much electric power (in kW) does the heat pump use to deliver 19.0 kJ/s of heat energy to the house?
Express your answer in kilowatts.
► View Available Hint(s)
Win =
Submit
Part B
Cost₁ =
17 ΑΣΦ
Submit
What does one month's heating cost in the home with a 19.0 kW electric heater?
Express your answer in dollars.
► View Available Hint(s)
?
VE ΑΣΦ
kW
?
$
Transcribed Image Text:A heat engine running backward is called a refrigerator if its purpose is to extract heat from a cold reservoir. The same engine running backward is called a heat pump if its purpose is to exhaust warm air into the hot reservoir. Heat pumps are widely used for home heating. You can think of a heat pump as a refrigerator that is cooling the already cold outdoors and, with its exhaust heat QH, warming the indoors. Perhaps this seems a little silly, but consider the following. Electricity can be directly used to heat a home by passing an electric current through a heating coil. This is a direct, 100% conversion of work to heat. That is, 19.0 kW of electric power (generated by doing work at the rate 19.0 kJ/s at the power plant) produces heat energy inside the home at a rate of 19.0 kJ/s. Suppose that the neighbor's home has a heat pump with a coefficient of performance of 3.00, a realistic value. NOTE: With a refrigerator, "what you get" is heat removed. But with a heat pump, "what you get" is heat delivered. So the coefficient of performance of a heat pump is K = QH/Win. An average price for electricity is about 40 MJ per dollar. A furnace or heat pump will run typically 250 hours per month during the winter. How much electric power (in kW) does the heat pump use to deliver 19.0 kJ/s of heat energy to the house? Express your answer in kilowatts. ► View Available Hint(s) Win = Submit Part B Cost₁ = 17 ΑΣΦ Submit What does one month's heating cost in the home with a 19.0 kW electric heater? Express your answer in dollars. ► View Available Hint(s) ? VE ΑΣΦ kW ? $
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 4 steps with 4 images

Blurred answer
Knowledge Booster
Second law of thermodynamics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics (14th Edition)
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
Introduction To Quantum Mechanics
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
Physics for Scientists and Engineers
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley
College Physics: A Strategic Approach (4th Editio…
College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON