A heart defibrillator delivering 400 J of energy by discharging a capacitor initially at 10,000 V has a capacitance of 8.00 μF (see Example 18.11 of the textbook). The energy stored in the capacitor of a second defibrillator is only 296 J but the charg both defibrillators is the same. What is the voltage (in V) of the second defibrillator?
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Water constitutes about 70% of earth. Some important distinguishing properties of water are high molar concentration, small dissociation constant and high dielectric constant.
Electrostatic Potential and Capacitance
An electrostatic force is a force caused by stationary electric charges /fields. The electrostatic force is caused by the transfer of electrons in conducting materials. Coulomb’s law determines the amount of force between two stationary, charged particles. The electric force is the force which acts between two stationary charges. It is also called Coulomb force.
Given,
Energy delivering = 400J
Voltage = 10000
Capacitance = 8 microfarad
We need to calculate,
If energy stored =296J
Voltage of second defibrillator =?
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