A “hawser" is wrapped around a fixed "capstan" to secure a ship from docking. The tension in the rope caused by the ship is 1500 lb and the greatest horizontal force that a longshoreman can exert on the rope is 50 lb. The coefficient of static friction is µs= 0.30. Determine the least number of complete turns the rope must be wrapped around the capstan in order to prevent slipping of the rope. 50 lb 1500 Ib
A “hawser" is wrapped around a fixed "capstan" to secure a ship from docking. The tension in the rope caused by the ship is 1500 lb and the greatest horizontal force that a longshoreman can exert on the rope is 50 lb. The coefficient of static friction is µs= 0.30. Determine the least number of complete turns the rope must be wrapped around the capstan in order to prevent slipping of the rope. 50 lb 1500 Ib
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:A “hawser" is wrapped around a fixed “capstan" to secure a ship from docking. The tension in
the rope caused by the ship is 1500 lb and the greatest horizontal force that a longshoreman can
exert on the rope is 50 lb. The coefficient of static friction is us= 0.30. Determine the least number
of complete turns the rope must be wrapped around the capstan in order to prevent slipping of
the rope.
50 lb
1500 lb
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