## Projectile Motion Problem**Problem Statement:**A gun is fired with a muzzle velocity of 1193 feet per second at a target 3650 feet away. Find the minimum angle of elevation necessary to hit the target.Assume the initial height of the bullet is 0 feet, neglect air resistance, and give your answer in **degrees**.**Input Box:**- [ ]**Additional Resources:**- [Question Help:

Name: ## Projectile Motion Problem**Problem Statement:**A gun is fired with
Uploaded: 2024-03-20T06:57:47.000Z
Channel: Bartleby
Description: ## Projectile Motion Problem**Problem Statement:**A gun is fired with a muzzle velocity of 1193 feet per second at a target 3650 feet away. Find the minimum angle of elevation necessary to hit the target.Assume the initial height of the bullet is 0

The range(R) of a function projected at an angle with an initial velocity v is given by the…

Answered: A gun is fired with muzzle velocity…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Concept explainers

Topic Video

Question

## Projectile Motion Problem

**Problem Statement:**

A gun is fired with a muzzle velocity of 1193 feet per second at a target 3650 feet away. Find the minimum angle of elevation necessary to hit the target.

Assume the initial height of the bullet is 0 feet, neglect air resistance, and give your answer in **degrees**.

**Input Box:**
- [ ]

**Additional Resources:**
- [Question Help:

Expert Solution

Step 1: Determine the given variables

The range(R) of a function projected at an angle $theta$ with an initial velocity v is given by the equation ;

$R equals fraction numerator v squared sin space 2 theta over denominator g end fraction$

where g is the acceleration due to gravity .

Velocity of bullet is (v)= 1193 ft/s

Distance of Target (R)= 3650 ft

Acceleration due to gravity, g = 32.17 ft/s²

Step by step

Solved in 3 steps with 3 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions