A guitar has 4 strings. The mass per unit length of the G string is 4 times the mass per unit length of the E string. If they are both connected to the guitar and tightened to a tension of 100 N how does the fundamental wavelength of the E string compare to the fundamental wavelength of the G string?

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Chapter1: Units, Trigonometry. And Vectors
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48. A guitar has 4 strings. The mass per unit length of the G string is 4 times the mass per unit length of the E string. If they are both connected to the
guitar and tightened to a tension of 100 N how does the fundamental wavelength of the E string compare to the fundamental wavelength of the G
string?
O A. AE = AG
O B. AE = 2AG
OC AE =3AG
D. AE =4XG
O E. 2Ag = AG
%3D
OF. 3AE = AG
O C. 4Ag = AG
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Transcribed Image Text:Shi 48. A guitar has 4 strings. The mass per unit length of the G string is 4 times the mass per unit length of the E string. If they are both connected to the guitar and tightened to a tension of 100 N how does the fundamental wavelength of the E string compare to the fundamental wavelength of the G string? O A. AE = AG O B. AE = 2AG OC AE =3AG D. AE =4XG O E. 2Ag = AG %3D OF. 3AE = AG O C. 4Ag = AG Back Save & Continue 2020 BYU All rights res
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