### Calculating the Maximum Number of People for an Amusement Park VisitA group of friends wants to go to the amusement park. They have no more than $405 to spend on parking and admission. Parking costs $20, and tickets cost $38.50 per person, including tax. Which inequality can be used to determine $ x $, the maximum number of people who can go to the amusement park?#### Inequality Options:1. $ 38.5 + 20x \leq 405 $2. $ 20 + 38.5x \leq 405 $3. $ 38.5 + 20x \geq 405 $4. $ 20 + 38.5x \geq 405 $#### Explanation:The total cost includes a fixed parking fee of $20 and the individual ticket cost of $38.50 per person. Therefore, the total cost for $ x $ people can be expressed as:\[ 20 + 38.5x \leq 405 \]This means that the correct choice is:\[ \boxed{20 + 38.5x \leq 405} \]### Detailed Breakdown:- **Parking Cost:** $20- **Ticket Cost per Person:** $38.50- **Total Budget:** $405To form the inequality, add the fixed parking cost to the product of the ticket cost per person and the number of people:\[ 20 + 38.5x \leq 405 \]This inequality can now be solved to find the maximum number of people $ x $ who can attend within the budget.

Answered: Image /qna-images/answer/f63f2848-aade-4410-a0fb-ee6b18d8067c.jpg

A group of friends wants to go to the amusement park. They have no more than $405 to spend on parking and admission. Parking is $20, and tickets cost $38.50 per person, including tax. Which inequality can be used to determine x, the maximum number of people who can go to the amusement park? O 38.5+20x405 38.5+20x405 20+ 38.5x405 20+38.5r > 405

A group of friends wants to go to the amusement park. They have no more than $405 to spend on parking and admission. Parking is $20, and tickets cost $38.50 per person, including tax. Which inequality can be used to determine x, the maximum number of people who can go to the amusement park? O 38.5+20x405 38.5+20x405 20+ 38.5x405 20+38.5r > 405

Algebra and Trigonometry (6th Edition)

6th Edition

ISBN:9780134463216

Author:Robert F. Blitzer

Publisher:Robert F. Blitzer

ChapterP: Prerequisites: Fundamental Concepts Of Algebra

Section: Chapter Questions

Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...

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Question

### Calculating the Maximum Number of People for an Amusement Park Visit

A group of friends wants to go to the amusement park. They have no more than $405 to spend on parking and admission. Parking costs $20, and tickets cost $38.50 per person, including tax. Which inequality can be used to determine $ x $, the maximum number of people who can go to the amusement park?

#### Inequality Options:
1. $ 38.5 + 20x \leq 405 $
2. $ 20 + 38.5x \leq 405 $
3. $ 38.5 + 20x \geq 405 $
4. $ 20 + 38.5x \geq 405 $

#### Explanation:
The total cost includes a fixed parking fee of $20 and the individual ticket cost of $38.50 per person. Therefore, the total cost for $ x $ people can be expressed as:
\[ 20 + 38.5x \leq 405 \]

This means that the correct choice is:
\[ \boxed{20 + 38.5x \leq 405} \]

### Detailed Breakdown:
- **Parking Cost:** $20
- **Ticket Cost per Person:** $38.50
- **Total Budget:** $405

To form the inequality, add the fixed parking cost to the product of the ticket cost per person and the number of people:
\[ 20 + 38.5x \leq 405 \]

This inequality can now be solved to find the maximum number of people $ x $ who can attend within the budget.

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