A grinding machine will be qualified for a particular task if it can be shown to pro-duce less than 8% defective parts. In a random sample of 300 parts, 12 were defective.4.You may use Minitab or other software for this problem, but you must show enough stepsthat it is clear that you understand the procedure(s) you are using.(a)0.08? Perform an appropriate hypothesis test.Do the data provide evidence that the probability of a defective part is belowCalculate a 99% confidence interval for the probability of a defective part. Use(b)the quick-and-dirty confidence interval method to test whether the probability of a de-fective part is 0.08.(c)Do your answers in parts (a) and (b) agree about whether the probability isbelow 0.08?

Answered: A grinding machine will be qualified…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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You are to roll a fair die n = 120 times, each time observing if the topside of the die shows a 6 (success) or not (failure). After observing the n = 120 tosses, you are to count the number of times the topside showed a 6. This count is represented by the random variable X. (a) The distribution of X ? with a mean and a standard deviation Enter your answer using all the decimals you can. (b) Now think about the proportion of your n = 120 tosses that show a six. What can you say about the distribution of this proportion? Complete the sentence, Enter your answer using all the decimals you can. The distribution of ? with a mean and a standard deviation σ you can. ☐ 2 2 ☐ (c) What is the probability that the proportion/percentage of your n = 120 tosses that show a six will be somewhere between 15% and 22%? Enter your answer using all the decimals you can. (d) After the n = 120 tosses of the die, you observe X = 27, the value of the sample proportion is then = 270 = 0.225. What is the…
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Consider the experiment of tossing a coin twice...please check my work List the experimental outcomes. Let H=Heads & T=Tails Define a random variable that represents the number of heads occurring on the two tosses. Show what value the random variable would assume for each of the experimental outcomes.
Show all your work Indicate clearly the methods you use, because you will be scored on the correctness of your methods as well as on the accuracy and completeness of your results and explanations. Researchers are studying two populations of sea turtles, In population D. 30 percent of the turties have a shell length greater than 2 feet. In population E. 20 percent of the turtles have a shell length greater than 2 feet. Froma random sample of 40 turtes selected from D.15 had a shell length greater than 2 feet. From a random sample of 60 turtles selected fromE. 11 had a shell length greater than 2 feet. Let pry represent the sample proportion for D, and let p represent the sample proportion for E (a)What is the value of the difference pryPr?Show your work. (b) What are the mean and standard deviation of the sampling distribution of the difference in sample proportions p P:? Show your work and label each value. (c) Can it be assumed that the sampling distribution of the difference of the…
A process yields 10% defective items. If 100 items are randomly selected from the process, use normal approximation to find the following probabilities, where X is a binomial random variable. QUESTION: 1. The number of defectives exceeds 13. NOTE: Answer in 4 decimal places. 2. The number of defectives is less than 8. NOTE: Answer in 4 decimal places.
Q3
A researcher claims that 45% of U.S. adults think that the IRS is not aggressive enough in pursuing people who cheat on their taxes. You believe the true percentage is more than 45%. To test this, you take a simple random sample of 400 U.S. adults and find that 208 of them say the IRS is not aggressive enough. Test at .05 significance. Round to the fourth Ho: P HA: P How many successes were there? Test Statistic: = ४ .45 .45 P-value: Did something significant happen? Significance Happened Select the Decision Rule: Reject the Null There is Oenough evidence to conclude that more than 45% of U.S. adults think that the IRS is not aggressive enough in pursuing people who cheat on their taxes. ✓
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40. We will take a random sample of 30 vehicles of a certain make and model and measure the fuel efficiency in miles per gallon (mpg) of each of them. We will conduct a hypothesis test at the 10% level of significance to determine whether there is evidence that the true mean fuel efficiency of all cars of this make and model differs from 32 mpg. What is the probability of failing to reject H, if the true mean is in fact 32 mpg? (A) 0.10 (B) 0.95 (C) 0.05 (D) 0.90 (E) 0.20
← In a random sample of males, it was found that 18 write with their left hands and 212 do not. In a random sample of females, it was found that 66 write with their left hands and 440 do not. Use a 0.05 significance level to test the claim that the rate of left-handedness among males is less than that among females. Complete parts (a) through (c) below. ✓ 1319 K H₁: P₁ OD. Ho: P₁ P₂ H₁: P₁ P₂ Identify the test statistic. Z= -2.06 (Round to two decimal places as needed.) Identify the P-value. P-value = 0.020 (Round to three decimal places as needed.) What is the conclusion based on the hypothesis test? w an example Get more help. P2 The P-value is less than the significance level of a = 0.05, so males is less than that among females. b. Test the claim by constructing an appropriate confidence interval. The 90% confidence interval is Clear all : ; I d F11 { + [ option = ? Check answer 11 I } * 1
N 14 problem. che cable shows the number of smokers in a random sample of 500 adults aged 20-24 nd the number of smokers in a random sample of 450 adults aged 25-29. Assume that you plan to use a significance level of alpha 0.10 to test the claim that pı p2- Find the critical value(s) for this hypothesis test. Do the data provide sufficient evidence that the proportion of smokers in the 20-24 age group is different from the proportion of smokers in the 25-29 age group? Age 20-24 500 Age 25-29 450 Number in sample Number of smokers 110 63 z = 1.645: yes z = + 1.28; yes O z = + 1.96; no z = 1.28; no

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