A graphing calculator may be used for the following problem. = . +e-8x + 1 f(x)%3D R 2 9(x) = 5x2 + 4x + 2. -2+ Let f and g be the functions defined by f)= x+e +1, and g(x) = - + 4x +2. Let Q and R be the two regions enclosed by the graphs of fand g shown in the figure above. %3D a) Find the sum of the areas of regions Q and R. b) The region Q is the base of a solid whose cross sections perpendicular to the x-axis are squares. Find the volume of the solid. c) The vertical line x = k divides region R into two equal regions with equal areas. Write, but do not solve, an equation involving integral expressions whose solutions give the value k. B.

A graphing calculator may be used for the following problem. = . +e-8x + 1 f(x)%3D R 2 9(x) = 5x2 + 4x + 2. -2+ Let f and g be the functions defined by f)= x+e +1, and g(x) = - + 4x +2. Let Q and R be the two regions enclosed by the graphs of fand g shown in the figure above. %3D a) Find the sum of the areas of regions Q and R. b) The region Q is the base of a solid whose cross sections perpendicular to the x-axis are squares. Find the volume of the solid. c) The vertical line x = k divides region R into two equal regions with equal areas. Write, but do not solve, an equation involving integral expressions whose solutions give the value k. B.

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Concept explainers

Optimization

Optimization comes from the same root as "optimal". "Optimal" means the highest. When you do the optimization process, that is when you are "making it best" to maximize everything and to achieve optimal results, a set of parameters is the base for the selection of the best element for a given system.

Integration

Integration means to sum the things. In mathematics, it is the branch of Calculus which is used to find the area under the curve. The operation subtraction is the inverse of addition, division is the inverse of multiplication. In the same way, integration and differentiation are inverse operators. Differential equations give a relation between a function and its derivative.

Application of Integration

In mathematics, the process of integration is used to compute complex area related problems. With the application of integration, solving area related problems, whether they are a curve, or a curve between lines, can be done easily.

Volume

In mathematics, we describe the term volume as a quantity that can express the total space that an object occupies at any point in time. Usually, volumes can only be calculated for 3-dimensional objects. By 3-dimensional or 3D objects, we mean objects that have length, breadth, and height (or depth).

Area

Area refers to the amount of space a figure encloses and the number of square units that cover a shape. It is two-dimensional and is measured in square units.

Question

(panunuopt.apınouapni
FRQ 2
A graphing calculator may be used for the following problem.
fox) =
7x
+1
-8x+ 1
9.
R.
2.
9.
+4x+2
2.
Let fand g be the functions defined by fA)=*e*+1, and g(x) = -+4x+2
the two regions enclosed by the graphs of f and g shown in the figure above.
Let Q and R be
a) Find the sum of the areas of regions Q and R.
b) The region Q is the base of a solid whose cross sections perpendicular to thex-axis are squares.
Find the volume of the solid.
c) The vertical line x = k divides region R into two equal regions with equal areas. Write, but do not
solve, an equation involving integral expressions whose solutions give the value k.

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Given that r(*) =-1 and g(*) = 5 - x. (i) Plot the graph of y= r(x) and y = g(x) on a graph paper for values of x between -4 and 4. Show clearly both x and y axes, x-intercepts and y- intercept for both fnctions. (ii) Find the intersection points for these two graphs.
Match the graph to one of the following functions. -3 3 X O y = -(x + 2)2 O y = -|x| + 2 O y = -2x2 Oy = -|x + 2| Oy = |x - 2| O y = |x| + 2 O y = -x2 + 2 O y = 2|x| Oy = -2|x| Oy = (x - 2)2 Oy = x2 + 2 Oy = 2x2
2. For the given functions f and g, each of the following: (f + g)(x), (f – g)(x), (f · g)(x), and ()(x), (f + g)(5), (f - g)(3), (f · g)(2), and ()(1). f(x) = 2x + 5 9x - 1 %3D g(x) = 3x + 4 %3D 2x + 5
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