A graphing calculator is recommended. Consider the following. cos(x) = x3 (a) Prove that the equation has at least one real solution. The equation cos(x) = x³ is equivalent to the equation f(x) = cos(x) - x³ = 0. f(x) is continuous on the interval [0, 1], f(0) = that f(c) = 0 by the Intermediate Value Theorem. Thus, there is a root of the equation cos(x) = x³, in the interval (0, 1). , and f(1) = (b) Use a calculator to find an interval length 0.01 that contains a solution. (Enter your answer using interval notation. Round your answers to two decimal places.) . Since ---Select--- < 0 <--Select---, there is a number c in (0, 1) such

A graphing calculator is recommended. Consider the following. cos(x) = x3 (a) Prove that the equation has at least one real solution. The equation cos(x) = x³ is equivalent to the equation f(x) = cos(x) - x³ = 0. f(x) is continuous on the interval [0, 1], f(0) = that f(c) = 0 by the Intermediate Value Theorem. Thus, there is a root of the equation cos(x) = x³, in the interval (0, 1). , and f(1) = (b) Use a calculator to find an interval length 0.01 that contains a solution. (Enter your answer using interval notation. Round your answers to two decimal places.) . Since ---Select--- < 0 <--Select---, there is a number c in (0, 1) such

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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