A gram of gasoline produces 45.0 kJ of energy when burned. Gasoline has a density of 0.77 g/mL. How would you calculate the amount of energy produced by burning 44. L of gasoline? Set the math up. But don't do any of it. Just leave your answer as a math expression. Also, be sure your answer includes all the correct unit symbols. energy produced = x10 DO 0.0

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Title: Calculating Energy from Combustion of Gasoline

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**Problem Statement:**

A gram of gasoline produces 45.0 kJ of energy when burned. Gasoline has a density of 0.77 g/mL. How would you calculate the amount of energy produced by burning 44.0 L of gasoline?

**Instructions:**

1. **Set up the Calculation:**
   - Do not perform the calculation. Leave your answer as a mathematical expression.
   - Ensure your answer includes all correct unit symbols.

**Solution Setup:**

The energy produced by burning gasoline can be calculated using the formula:

\[
\text{Energy produced} = \left( \frac{\text{kJ}}{\text{g}} \right) \times \left( \frac{\text{g}}{\text{mL}} \right) \times \left( \text{mL} \right)
\]

Where:
- 45.0 kJ/g is the energy produced per gram.
- 0.77 g/mL is the density of gasoline.
- 44,000 mL is the volume of gasoline since 44.0 L = 44,000 mL.

**Graphical Interface:**

There is a section with input fields allowing mathematical symbols and expressions to be constructed, ensuring users format their responses correctly, including unit symbols.

**Note:**

Remember to consider unit conversions, especially from liters to milliliters (1 L = 1000 mL), before setting up the expression.

(End of Content)
Transcribed Image Text:Title: Calculating Energy from Combustion of Gasoline --- **Problem Statement:** A gram of gasoline produces 45.0 kJ of energy when burned. Gasoline has a density of 0.77 g/mL. How would you calculate the amount of energy produced by burning 44.0 L of gasoline? **Instructions:** 1. **Set up the Calculation:** - Do not perform the calculation. Leave your answer as a mathematical expression. - Ensure your answer includes all correct unit symbols. **Solution Setup:** The energy produced by burning gasoline can be calculated using the formula: \[ \text{Energy produced} = \left( \frac{\text{kJ}}{\text{g}} \right) \times \left( \frac{\text{g}}{\text{mL}} \right) \times \left( \text{mL} \right) \] Where: - 45.0 kJ/g is the energy produced per gram. - 0.77 g/mL is the density of gasoline. - 44,000 mL is the volume of gasoline since 44.0 L = 44,000 mL. **Graphical Interface:** There is a section with input fields allowing mathematical symbols and expressions to be constructed, ensuring users format their responses correctly, including unit symbols. **Note:** Remember to consider unit conversions, especially from liters to milliliters (1 L = 1000 mL), before setting up the expression. (End of Content)
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