A graduated cylinder filled with water. A cube is dropped into the cylinder and the water rises. See Figure 2. The cube is only partially submerged. The length of a side of the cube is 3.7 cm. Assume the specific weight of water is 9.81 kN/m3 Required: a) What is the submerged volume of the cube in cm3? b) What is the weight of the cube in Newtons? c) What is the specific weight of the cube in kN/m2? Is it less than specific weight of water?
A graduated cylinder filled with water. A cube is dropped into the cylinder and the water rises. See Figure 2. The cube is only partially submerged. The length of a side of the cube is 3.7 cm. Assume the specific weight of water is 9.81 kN/m3 Required: a) What is the submerged volume of the cube in cm3? b) What is the weight of the cube in Newtons? c) What is the specific weight of the cube in kN/m2? Is it less than specific weight of water?
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Problem 2
Given: A graduated cylinder filled with water. A cube is dropped into the cylinder and the water rises. See Figure 2. The cube is only partially submerged. The length of a side of the cube is 3.7 cm. Assume the specific weight of water is 9.81 kN/m3
Required:
a) What is the submerged volume of the cube in cm3?
b) What is the weight of the cube in Newtons?
c) What is the specific weight of the cube in kN/m2? Is it less than specific weight of water?

Transcribed Image Text:The image shows two sets of beakers used to demonstrate the displacement method for measuring the volume of irregular objects.
### Figure 1:
- **Left Beaker**: Contains a liquid filled to the 100 mL mark.
- **Right Beaker**: The same beaker with an irregularly shaped object submerged in the liquid. The water level rises to the 150 mL mark.
**Explanation**: The volume of the irregular object can be determined by subtracting the initial volume of water (100 mL) from the final volume (150 mL), which results in a volume of 50 mL for the object.
### Figure 2:
- **Left Beaker**: Contains a liquid filled to the 150 mL mark.
- **Right Beaker**: The same beaker with a regular cube submerged. The water level rises to the 200 mL mark.
**Explanation**: The volume of the cube is calculated by subtracting the initial water level (150 mL) from the final level (200 mL), resulting in a volume of 50 mL for the cube.
Both figures illustrate the principle of water displacement to measure an object's volume, useful for both regular and irregularly shaped objects.
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