A government agency provides the number of miles that residents of the 75 largest metropolitan areas travel per day in a car. Suppose that for a simple random sample of 50 City A residents the mean is 22.8 miles a day and the standard deviation is 8.2 miles a day, and for an independent simple random sample of 40 City B residents the mean is 18.3 miles a day and the standard deviation is 7.2 miles a day. (a) What is the point estimate of the difference between the mean number of miles that City A residents travel per day and the mean number of miles that City B residents travel per day? (Use City A - City B.). 4.5 mi/day (b) What is the 95% confidence interval for the difference between the two population means (in miles per day)? (Use City A - answers to one decimal place.) 1.2 xmi/day to 7.8 x mi/day City B. Round your

Q: I also Need help with part D please

A: The correlation coefficient is 0.8137.

Q: can you do the next two parts please

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A: Given,         ∫2416-25n2dn

Q: How do you solve this problem?

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Q: can you do the next part

A: The set of vector  and We have to express the vector  in terms of the given set of vector

Q: okay can you also do part b now.

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Q: Thank you so much

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Q: Please solution for part G,  Thanks!

A: (g) n=50, P(∑i=150Xi&lt;1124.54)=?

Q: Can you answer this question please?

A: Hey, since there is multiple sub part questions posted, we will answer first three sub part…