A golfer makes a successful chip shot to the green. Suppose the path of the ball from the moment it s struck to the moment it hits the green S described by y=13.51x-0.62x² where x E [0, b where x is the horizontal distance (in yards) From the point where the ball was struck, nd y is the vertical distance (in yards) abov he fairway. a.) set up the integral (to just before integrat to find the distance the ball trave (the arc length) from the moment it Struck to the moment it hits green. b.) If the ball travels 42 yards Chori down the fairway, find the arc le the ball travels. Round the near hundred.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Question
**Title: Calculating the Arc Length of a Golf Ball's Path**

A golfer makes a successful chip shot to the green. Suppose the path of the ball from the moment it is struck to the moment it hits the green is described by the equation:

\[ y = 13.51x - 0.62x^2 \]

where \( x \) is the horizontal distance (in yards) from the point where the ball was struck, and \( y \) is the vertical distance (in yards) above the fairway.

Given these parameters:
- \( x \) belongs to the interval \([0, b]\)

### Problem Statement:
#### Part (a):
Set up the integral (to just before integrating) to find the distance the ball travels (the arc length) from the moment it is struck to the moment it hits the green.

#### Part (b):
If the ball travels 42 yards (horizontally) down the fairway, find the arc length the ball travels. Round to the nearest hundred.

### Solution Outline:
#### Part (a):
To find the arc length \( L \) of the path of the ball, we use the formula for the arc length of a curve given by the function \( y = f(x) \):

\[ L = \int_{a}^{b} \sqrt{1 + \left( \frac{dy}{dx} \right)^2 } \, dx \]

First, we need to find \( \frac{dy}{dx} \):
\[ y = 13.51x - 0.62x^2 \]
\[ \frac{dy}{dx} = 13.51 - 1.24x \]

Thus, the integrand becomes:
\[ 1 + \left( 13.51 - 1.24x \right)^2 \]

Therefore, the integral to find the arc length \( L \) is:
\[ L = \int_{0}^{b} \sqrt{1 + \left(13.51 - 1.24x \right)^2 } \, dx \]

#### Part (b):
If the ball travels 42 yards horizontally (\( x = 42 \)):

\[ L = \int_{0}^{42} \sqrt{1 + \left(13.51 - 1.24x \right)^2 } \, dx \]

To solve this integral, numerical methods or software tools
Transcribed Image Text:**Title: Calculating the Arc Length of a Golf Ball's Path** A golfer makes a successful chip shot to the green. Suppose the path of the ball from the moment it is struck to the moment it hits the green is described by the equation: \[ y = 13.51x - 0.62x^2 \] where \( x \) is the horizontal distance (in yards) from the point where the ball was struck, and \( y \) is the vertical distance (in yards) above the fairway. Given these parameters: - \( x \) belongs to the interval \([0, b]\) ### Problem Statement: #### Part (a): Set up the integral (to just before integrating) to find the distance the ball travels (the arc length) from the moment it is struck to the moment it hits the green. #### Part (b): If the ball travels 42 yards (horizontally) down the fairway, find the arc length the ball travels. Round to the nearest hundred. ### Solution Outline: #### Part (a): To find the arc length \( L \) of the path of the ball, we use the formula for the arc length of a curve given by the function \( y = f(x) \): \[ L = \int_{a}^{b} \sqrt{1 + \left( \frac{dy}{dx} \right)^2 } \, dx \] First, we need to find \( \frac{dy}{dx} \): \[ y = 13.51x - 0.62x^2 \] \[ \frac{dy}{dx} = 13.51 - 1.24x \] Thus, the integrand becomes: \[ 1 + \left( 13.51 - 1.24x \right)^2 \] Therefore, the integral to find the arc length \( L \) is: \[ L = \int_{0}^{b} \sqrt{1 + \left(13.51 - 1.24x \right)^2 } \, dx \] #### Part (b): If the ball travels 42 yards horizontally (\( x = 42 \)): \[ L = \int_{0}^{42} \sqrt{1 + \left(13.51 - 1.24x \right)^2 } \, dx \] To solve this integral, numerical methods or software tools
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