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A golf ball is hit horizontally off the edge of a 29 m high cliff and lands a distance of 21 m from the edge of the cliff. What was the initial vertical velocity of the golf ball, in m/s? Answer: m/s

A golf ball is hit horizontally off the edge of a 29 m high cliff and lands a distance of 21 m from the edge of the cliff. What was the initial vertical velocity of the golf ball, in m/s? Answer: m/s

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Physics Problem: Horizontal Projectile Motion** A golf ball is hit horizontally off the edge of a 29 m high cliff and lands a distance of 21 m from the edge of the cliff. What was the initial vertical velocity of the golf ball, in m/s? **Answer:** _______ m/s **Explanation:** This problem involves analyzing the motion of a projectile. The key aspects to consider are: - **Initial Vertical Velocity**: Since the ball is hit horizontally, the initial vertical velocity is 0 m/s. - **Horizontal Distance (Range)**: 21 m - **Vertical Distance (Height)**: 29 m To solve for the initial velocity, use the kinematic equations and the principles of projectile motion. An understanding of both horizontal and vertical motion components is necessary, where: - Horizontal motion is constant velocity. - Vertical motion is consistently accelerated due to gravity (9.81 m/s² downward).
Transcribed Image Text:**Physics Problem: Horizontal Projectile Motion** A golf ball is hit horizontally off the edge of a 29 m high cliff and lands a distance of 21 m from the edge of the cliff. What was the initial vertical velocity of the golf ball, in m/s? **Answer:** _______ m/s **Explanation:** This problem involves analyzing the motion of a projectile. The key aspects to consider are: - **Initial Vertical Velocity**: Since the ball is hit horizontally, the initial vertical velocity is 0 m/s. - **Horizontal Distance (Range)**: 21 m - **Vertical Distance (Height)**: 29 m To solve for the initial velocity, use the kinematic equations and the principles of projectile motion. An understanding of both horizontal and vertical motion components is necessary, where: - Horizontal motion is constant velocity. - Vertical motion is consistently accelerated due to gravity (9.81 m/s² downward).
Expert Solution
Step 1

Write the given values with the suitable variables.

h=29 md=21 m

Here, h is the height of a cliff and d is the horizontal distance from the edge of a cliff.

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