#23 A golf association requires that golf balls have a diameter that is 1.68 inches. To determine if golf balls conform to the standard, a random sample of golf balls was selected. Their diameters are shown inthe accompanying data table. Do the golf balls conform to the standards? Use the a = 0.01 level of significance.Click here to view the data on golf ball diameters.Click here to view the table of critical t-values.Ho:= ||1.68H :1.68(Type integers or decimals. Do not round.)Find the test statistic.(Round to two decimal places as needed.)Approximate the P-value.The P-value is in the rangeWhat can be concluded from the hypothesis test?O A. Reject Ho. There is sufficient evidence to conclude that the golf balls do not conform to the association's standards at the a = 0.01 level of significance.B. Do not reject Ho. There is not sufficient evidence to conclude that the golf balls do not conform to the association's standards at the oa = 0.01 level of significance.C. Do not reject Ho. There is sufficient evidence to conclude that the golf balls do not conform to the association's standards at the a = 0.01 level of significance.O D. Reject Ho. There is not sufficient evidence to conclude that the golf balls do not conform to the association's standards at the a = 0.01 level of significance.Click to select your answer(s).Save for Later Golf Ball DiametersGolf Ball Diameter (inches)1.6831.6761.6821.6861.6771.6851.6841.6851.6731.6851.6821.674PrintDone

Name: #23 A golf association requires that golf balls have a diameter that i
Uploaded: 2024-03-05T11:52:21.000Z
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Description: #23 A golf association requires that golf balls have a diameter that is 1.68 inches. To determine if golf balls conform to the standard, a random sample of golf balls was selected. Their diameters are shown inthe accompanying data table. Do the golf

Given that, Sample size n=12 Sample mean x1¯=1.681 Sample standard deviation s=0.0047 Hypothesis: H0:μ=1.68 H1:μ≠1.68 Test statistic: t=x¯-μsn=1.681-1.680.004712=0.737P-value: The two tailed P-value for the t-test at 11 degrees of freedom can be obtained using the excel formula, “=T.DIST.2T (0.737,11)” as follows: Decision rule: If p-value ≤ α, then reject the null hypothesis. Otherwise, fail to reject the null hypothesis. Conclusion: Here, p-value (=0.4765) is greater than the significance level (0.01). Therefore, do not reject the null hypothesis. Thus, there is sufficient evidence to conclude that the golf balls do not conform to the associations standards at the 0.01 level of significance. Thus, the correct option is C.