A gold wire 5.45 m long and of diameter 0.890 mm carries current of 1.25 A. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Electrical hazards in heart surgery. Part A Find the resistance of this wire. Express your answer in ohms. R = Submit Part B IVE ΑΣΦ V = Request Answer Find the potential difference between its ends. Express your answer in volts. 15. ΑΣΦ ? ? V

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A gold wire 5.45 m long and of diameter 0.890 mm
carries a current of 1.25 A.
For related problem-solving tips and strategies, you
may want to view a Video Tutor Solution of
Electrical hazards in heart surgery.
Part A
Find the resistance of this wire.
Express your answer in ohms.
R =
Submit
Part B
—| ΑΣΦ
V =
Request Answer
Find the potential difference between its ends.
Express your answer in volts.
| ΑΣΦ
?
?
Ω
V
Transcribed Image Text:A gold wire 5.45 m long and of diameter 0.890 mm carries a current of 1.25 A. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Electrical hazards in heart surgery. Part A Find the resistance of this wire. Express your answer in ohms. R = Submit Part B —| ΑΣΦ V = Request Answer Find the potential difference between its ends. Express your answer in volts. | ΑΣΦ ? ? Ω V
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