A Gold (Au) has a face-centered cubic structure with a unit cell edge length of 407.8 pm. What is the calculated value of the density of gold based on this information? 1 pm =1 x 10 -10 Avogadro's number = 6.022 x 1023 Molar mass of gold = 197 g/mol cm. Selected Answer: O d. 4.82 g/cm3 Answers: O a. 19.28 g/cm3 b. 11.6 g/cm3 c. 15.78 g/cm d. 4.82 g/cm3
A Gold (Au) has a face-centered cubic structure with a unit cell edge length of 407.8 pm. What is the calculated value of the density of gold based on this information? 1 pm =1 x 10 -10 Avogadro's number = 6.022 x 1023 Molar mass of gold = 197 g/mol cm. Selected Answer: O d. 4.82 g/cm3 Answers: O a. 19.28 g/cm3 b. 11.6 g/cm3 c. 15.78 g/cm d. 4.82 g/cm3
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Gold (Au) has a face-centered cubic structure with a unit cell edge length of 407.8 pm. What is the calculated value of the density of gold based on this information?
pm = 1 x 10
-10
cm.
Avogadro's number = 6.022 x 1023 Molar mass of gold = 197 g/mol
Selected Answer:
O d. 4.82 g/cm3
Answers:
O a. 19.28 g/cm3
b. 11.6 g/cm3
c. 15.78 g/cm3
d. 4.82 g/cm3
e. 9.64 g/cm3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff7e0b628-1887-4036-8cfa-486903c53c1e%2Fed2e6e05-ab36-4cff-8a3d-62cf679efc16%2Fh39bf2_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Gold (Au) has a face-centered cubic structure with a unit cell edge length of 407.8 pm. What is the calculated value of the density of gold based on this information?
pm = 1 x 10
-10
cm.
Avogadro's number = 6.022 x 1023 Molar mass of gold = 197 g/mol
Selected Answer:
O d. 4.82 g/cm3
Answers:
O a. 19.28 g/cm3
b. 11.6 g/cm3
c. 15.78 g/cm3
d. 4.82 g/cm3
e. 9.64 g/cm3
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