A glider with mass m = 0.240 kg sits on a frictionless horizontal air track, connected to a spring with force constant k = 4.70 N/m . You pull on the glider, stretching the spring 0.110 m , and then release it with no initial velocity. The glider begins to move back toward its equilibrium position (x=0). What must the initial displacement of the glider be if its maximum speed in the subsequent motion is to be 2.40 m/s ?

Q: A 2.50-kg mass is attached to a vertical spring with spring constant, k=96.0 N/m and allowed to…

A:

Q: A light spring with force constant 3.10 N/m is compressed by 7.80 cm as it is held between a…

A: Mass of left block=m1=0.4 kg  Mass of right block=m2=0.8kg Let acceleration of m1=a1 m/s^2  and…

Q: A 9.5 kg block is forced against a horizontal spring, compressing the spring 0.3 m. When released,…

A:

Q: A block on a frictionless horizontal surface is attached to a cable and a spring that is stretched…

A: Given data, Stretched in the spring = 0.17 m Tension in the cable = 48 N Normal force on the block =…

Q: A 5.00 ✕ 105 kg subway train is brought to a stop from a speed of 0.500 m/s in 0.500 m by a large…

A: Given data: Mass (m) = 5.00×105 kg Initial velocity (u) = 0.500 m/s Final velocity (v) = 0 m/s…

Q: A 0.55 kg block attached to a spring with force constant 131 N/m is free to move on a frictionless,…

A: Solution: Given that mass of the block m = 0.55 kg spring constant k =131 N/m spring strech x =0.13…

Q: The force law for a non-linear spring is F(x) = -60x1.15 N. Find the average force exerted by the…

A: This problem can be solved using the formula for the average of a function.

Q: A block of mass 15.0 kg slides from rest down a frictionless 40.0° incline and is stopped by a…

A: Given:Mass of the block, m = 15 kgInclination of the plane = 40 degreesSpring constant, k = 3.4 ×104…

Q: small block slides down a frictionless track whose shape is described by y = (x^2) /d for x0. The…

A: Given  At x =0, is given a push to left with an initial speed of 2.60 m/s.  So  Total energy at x=0…

Q: ith the string hanging vertically, the object is given an initial velocity of 1.9 m/s parallel to…

A:

Q: A 6.50 ✕ 105 kg subway train is brought to a stop from a speed of 0.600 m/s in 0.800 m by a large…

A: According to question---- Given data--- Mass m = 6.5 × 105 kg. Speed = 0.6 m / sec. X = 0.8 m. We…

Q: ⦁ A person (m=50 kg) is sitting on top of a wooden crate (m=100kg) on a wooden floor ( ). His friend…

A:

Q: A block with mass m1 = 8.7 kg is on an incline with an angle θ = 37° with respect to the horizontal.…

A: See below

Q: A mass m = 16 kg rests on a frictionless table and accelerated by a spring with spring constant k =…

A:

Q: A mass of 7.0 kg hangs from a spring attached to the ceiling. The spring has a spring constant of…

A: Spring force is given asF=k∆xK=spring constant∆x = stretches in spring

Q: A 26100 kg train is reaching the end of the line. In order to slow down, the front of the train…

A: Given Information:Mass of train m = 26100 kgVelocity of the train v = 62.5 m/sStiffness of the…

Q: A toy cannon uses a spring to project a 5.22-g soft rubber ball. The spring is originally compressed…

A: mass = 5.22 g original compression (d) = 4.93 cm k = 7.98 N/m d1 = 14.4 cm f = - 0.0316 N

Q: In the figure, a 4.2 kg block slides along a track from one level to a higher level after passing…

A:

Q: A 25.0 cm long spring is hung vertically from a ceiling and stretches to 32.5 cm when a 7.00 kg mass…

A: GIVEN        Length of the spring = L = 25 cm = 0.25 m        Mass hung from the free end of the…

Q: A pendulum consists of a 2 kg bob attached to a light string of length 6.0 m.  The bob is struck…

A:

Q: As a 1.4x104 kg jet plane lands on an aircraft carrier, its tail hook snags a cable to slow it down.…

A: Here we will find the speed of plane

Q: Block A (mass = 5.00 kg) is attached to a spring. Initially the spring is in its equilibrium…

A: Mass of block A is MA = 5 kg Mass of block B is MB = 2 kg The stretching in the spring at…

Q: k m A block of mass m = 5.20 kg is being suspended at rest by an extended spring of spring constant…

A: M = 5.2kg  K= 36 N/m  F= 20N  s= 2.45m

Q: A 2.90 kg block on a horizontal floor is attached to a horizontal spring that is initially…

A: Apply Newton’s second law at the vertical motion of the block, then

Q: A 69 g ice cube can slide without friction up and down a 30° slope. The ice cube is pressed against…

A:

Q: A 6.50 ✕ 105 kg subway train is brought to a stop from a speed of 0.500 m/s in 0.600 m by a large…

A: Given that - mass of the Subway train Speed of the train Distance from the spring bumper To Find -…

Q: A small block slides down a frictionless track whose shape is described by y = (x^2) /d for x0.The…

A:

Q: A box is motionless, sitting on a ramp with an incline of 0 =51.1 ° being pulled in the direction up…

A:

Q: A box of mass m = 0.31 kg is set against a spring with a spring constant of k1 = 549 N/m which has…

A: a)The required distance is,

Q: A 2.50-kg mass is attached to a vertical spring with spring constant, k=96.0 N/m and allowed to…

A: Given: The mass of the object is 2.5 kg. The spring constant is 96 N/m. The amplitude of the system…

Q: The problem uses the ideal spring force, in one dimension.  F = -kx, where x is the deviation from…

A: The maximum speed for a particle performing simple harmonic motion is given asv=AωA is the amplitude…

Spring Potential Energy

The potential energy is the energy possessed by a body by virtue of its position or the energy held by the object due to its position relative to other objects, its force like stresses, charge, and other factors affecting the particles of the body. The potential energy is the measure of the net work done by or on the body. The spring potential energy is the potential energy stored due to the deformation of an elastic spring and this elasticity is due to the stretched spring. The elasticity is the ability of a solid-state matter to come back to its equilibrium position or original position after any kind of external force is acted on it. It is also known as Elastic potential energy. The potential energy here is caused due to the displacement of the spring from its equilibrium position to another position and this potential energy is equal to the net work done due to the stretching of the spring. It also resembles the same mechanics of the oscillation of a simple pendulum, where due to the external force, the object moves from its equilibrium position to its maximum ends and the periodic motion continues till it comes back to the equilibrium position to rest.