a) Given that X ~ B(n,p) where n is a positive integer and 0
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- where appropriate. 1. Experience has shown that the seeds from a certain variety of orchid have a 75% chance of germinating when planted under normal conditions. Suppose n seeds are planted, and let X be the random variable that counts the number of seeds that germinate. (a) What type of random variable is X? Indicate both the type and the appropriate parameters using the "~" notation. Write down the pmf of X, and do not forget to indicate the range of values that x can take on. X ~ px (x) = = (b) What is the minimum value of n so that the probability of at least five of the seeds germinating is at least 90%?CALL CENTERExcopt for PANAMA) 1-800-SAMSUNG (1-800-726-75 6. For a population with a mean of u = 100 and a standard deviation of o = 20, a. Find the z-score for each of the following X values. X = 108 X = 115 X = 130 %3D %3D %3D X = 90 b. Find the score (X value) that corresponds to each of the following z-scores. X = 88 X = 95 z = -0.40 z = -0.50 z = 1.80 z = 0.75 Z = 1.50 Z = -1.25can you solve this for me by showing step by step for each question? Acme Food manufactures and sells bags of doughnuts whose weights follow a normal distribution with a mean of 400g and standard deviation 8g. a) Find the probability that a bag of doughnuts weights less than 410g b) Find P (X>412) c) Find P (395 < X < 404) d) The company can be prosecuted if the bags are less than 380g, if the company sells 50 bags per day find the expected number of bags under this weight. e) On a typical day 1.22% of bags are rejected as they are too heavy. Find the rejection weight.
- 6.- Assume that cans of Coke are filled so that the actual amounts have a mean of 12.00 oz and a standard deviation of 0.11 oz. a). Find the probability that a sample of 36 cans will have a mean amount of at least 12.19 oz. P( > 12.19) = b) Find x0 such that P(11.95 < X < x0 ) = 0.99Let a population consist of the values 7 cigarettes, 21 cigarettes, and 22 cigarettes smoked in a day. Show that when samples of size 2 are randomly selected with replacement, the samples have mean absolute deviations that do not center about the value of the mean absolute deviation of the population. What does this indicate about a sample mean absolute deviation being used as an estimator of the mean absolute deviation of a population? Calculate the mean absolute deviation for each possible sample of size 2 from the population. Sample Mean Absolute Deviation {7,7} __ {7,21} __ {7,22} __ {21,7} __ {21,21} __ {21,22} __ {22,7} __ {22,21} __ {22 ,22}Let x be a random variable that represents the weight of a lion in a certain region of Africa. Assume that x is normally distributed with a mean = 260 lbs . With standard deviation =30 lb Please include the graphs for questions A and B
- 1)When can a Standard Deviation for set of 5 numbers be zero? In other words, what kind of relationship must exist among all numbers in order for Standard Deviation to be zero Hint: Standard Deviation E(X¡ - Mean)²/(n – 1)Let a population consist of the values 11 cigarettes, 12 cigarettes, and 22 cigarettes smoked in a day. Show that when samples of size 2 are randomly selected with replacement, the samples have mean absolute deviations that do not center about the value of the mean absolute deviation of the population. What does this indicate about a sample mean absolute deviation being used as an estimator of the mean absolute deviation of a population? Calculate the mean absolute deviation for each possible sample of size 2 from the population. Mean Absolute Deviation Sample {11,11} {11,12} {11,22} {12,11} {12,12} {12,22} {22,11} {22,12} {22,22} (Type integers or decimals rounded to one decimal place as needed.) Budget Pi nd Pow....P Enter your answer in the edit fields and then click Check Answer. Clear All Check Answer partsA student takes a true-false test that has 10 questions and guesses randomly at each answer. LetX be the number of questions answered correctly. c)The mean and stand deviation of X (show work and round final answer to 2 decimal places) Mean: Standard deviation =
- 3) Answer each question using the list of numbers provided below and use STDEV equation provided. Hint: Standard Deviation = VE(Xi – Mean)²/(n – 1) - Set A {-16,0,16,15,25} Mean= Standard Deviation:A fast food restaurant boasts that their mean wait time in the drive-thru line is less than 3 minutes. Does the restaurant's claim hold true if the average wait time for 125 drive-thru customers is 2.82 minutes? (Assume σ = 1.16.)
