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A geometric sequence is given. Find the common ratio and write out the first four terms. {4} = 2 4 O A. r=2; U₁=2, U₂ = U3 = 3' O 2 8 = w/c 3' 2 4 8 16 B. r=₁=2, U₂3,43= 44 = 9' 27 4 U4 = 16 3 2 4 8 OC. = 3:41=3₁42 ₁43 = 27.44= 8 16 OD. r=2; U₁=2, U₂ = 3,43=₁44= 27 16 81

A geometric sequence is given. Find the common ratio and write out the first four terms. {4} = 2 4 O A. r=2; U₁=2, U₂ = U3 = 3' O 2 8 = w/c 3' 2 4 8 16 B. r=₁=2, U₂3,43= 44 = 9' 27 4 U4 = 16 3 2 4 8 OC. = 3:41=3₁42 ₁43 = 27.44= 8 16 OD. r=2; U₁=2, U₂ = 3,43=₁44= 27 16 81

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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A geometric sequence is given. Find the common ratio and write out the first four terms. {4} = 4 O A. r=2; U₁=2, U₂ = O 2 B. = 3' 2 U3 = 8 = wo/c 3' 2 4 8 3:41=2, 42 = 3, 43 = 9' U4 = 44 = 16 3 16 27 2 4 8 OC. = 341=3₁42 ₁43 = 27.44 = 4 8 16 OD. r=2; U₁ = 2₁ U₂ = 3, 43=₁ 44 = 27 16 81
Transcribed Image Text:A geometric sequence is given. Find the common ratio and write out the first four terms. {4} = 4 O A. r=2; U₁=2, U₂ = O 2 B. = 3' 2 U3 = 8 = wo/c 3' 2 4 8 3:41=2, 42 = 3, 43 = 9' U4 = 44 = 16 3 16 27 2 4 8 OC. = 341=3₁42 ₁43 = 27.44 = 4 8 16 OD. r=2; U₁ = 2₁ U₂ = 3, 43=₁ 44 = 27 16 81
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