A genetic experiment involving peas yielded one sample of offspring consisting of 439 green peas and 160 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 24% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. What are the null and alternative hypotheses? В. Но: р-0.24 H1: p>0.24 A. Ho: p+0.24 H1:p= 0.24 C. Ho: p#0.24 O D. Ho: p#0.24 H1:p>0.24 H1: p<0.24 O F. Ho: p= 0.24 E. Ho: p= 0.24 H1:p#0.24 H1:p<0.24 What is the test statistic? (Round to two decimal places as needed.) What is the P-value? P-value = (Round to four decimal places as needed.) What is the conclusion about the null hypothesis? A. Reject the null hypothesis because the P-value is greater than the significance level, a. B. Fail to reject the null hypothesis because the P-value is greater than the significance level, a. C. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a. D. Reject the null hypothesis because the P-value is less than or equal to the significance level, a. What is the final conclusion? A. There is not sufficient evidence to warrant rejection of the claim that 24% of offspring peas will be yellow. B. There is not sufficient evidence to support the claim that less than 24% of offspring peas will be yellow. C. There is sufficient evidence to warrant rejection of the claim that 24% of offspring peas will be yellow. D. There is sufficient evidence to support the claim that less than 24% of offspring peas will be yellow.
A genetic experiment involving peas yielded one sample of offspring consisting of 439 green peas and 160 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 24% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. What are the null and alternative hypotheses? В. Но: р-0.24 H1: p>0.24 A. Ho: p+0.24 H1:p= 0.24 C. Ho: p#0.24 O D. Ho: p#0.24 H1:p>0.24 H1: p<0.24 O F. Ho: p= 0.24 E. Ho: p= 0.24 H1:p#0.24 H1:p<0.24 What is the test statistic? (Round to two decimal places as needed.) What is the P-value? P-value = (Round to four decimal places as needed.) What is the conclusion about the null hypothesis? A. Reject the null hypothesis because the P-value is greater than the significance level, a. B. Fail to reject the null hypothesis because the P-value is greater than the significance level, a. C. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a. D. Reject the null hypothesis because the P-value is less than or equal to the significance level, a. What is the final conclusion? A. There is not sufficient evidence to warrant rejection of the claim that 24% of offspring peas will be yellow. B. There is not sufficient evidence to support the claim that less than 24% of offspring peas will be yellow. C. There is sufficient evidence to warrant rejection of the claim that 24% of offspring peas will be yellow. D. There is sufficient evidence to support the claim that less than 24% of offspring peas will be yellow.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:A genetic experiment involving peas yielded one sample of offspring consisting of 439 green peas and 160 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 24% of offspring peas will be yellow.
Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the
binomial distribution.
What are the null and alternative hypotheses?
В. Но: р-0.24
H1: p>0.24
A. Ho: p+0.24
H1:p= 0.24
C. Ho: p#0.24
O D. Ho: p#0.24
H1:p>0.24
H1: p<0.24
O F. Ho: p= 0.24
E. Ho: p= 0.24
H1:p#0.24
H1:p<0.24
What is the test statistic?
(Round to two decimal places as needed.)
What is the P-value?
P-value =
(Round to four decimal places as needed.)
Transcribed Image Text:What is the conclusion about the null hypothesis?
A. Reject the null hypothesis because the P-value is greater than the significance level, a.
B. Fail to reject the null hypothesis because the P-value is greater than the significance level, a.
C. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a.
D. Reject the null hypothesis because the P-value is less than or equal to the significance level, a.
What is the final conclusion?
A. There is not sufficient evidence to warrant rejection of the claim that 24% of offspring peas will be yellow.
B. There is not sufficient evidence to support the claim that less than 24% of offspring peas will be yellow.
C. There is sufficient evidence to warrant rejection of the claim that 24% of offspring peas will be yellow.
D. There is sufficient evidence to support the claim that less than 24% of offspring peas will be yellow.
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