A gazelle is grazing under a tree. At time t = 0 seconds, a cheetah, 100 m to the left of the tree, sees the gazelle and begins a chase. The following is a graph of the velocity of the cheetah's pursuit: 60- 40- 20- 10 12 -20- -40- -60- The cheetah's velocity fits the equation: v(t) = 0.1(t + 1)(t – 8)(t - 20) = 0.1(t3 – 27t2 + 132t + 160) %3D %3D where t is the time in seconds in the range 0

Advanced Engineering Mathematics
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Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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A gazelle is grazing under a tree. At time t 0 seconds, a cheetah, 100 m to the left of the
tree, sees the gazelle and begins a chase.
The following is a graph of the velocity of the cheetah's pursuit:
60-
40-
20-
10
12
-20-
-40-
-60-
The cheetah's velocity fits the equation:
v(t) = 0.1(t + 1)(t- 8)(t - 20) = 0.1(t3 - 27t2 + 132t + 160)
%3D
where t is the time in seconds in the
range 0 <t s 10.
The cheetah captures the gazelle time t = 10 seconds.
Assume the cheetah runs in a straight line.
i) What distance did the cheetah run during the 10 second chase?
ii) The graph shows the cheetah reached maximum velocity at some time between
time t=2 and t=D4 seconds.
At what time exactly did the cheetah reach this maximum velocity (to 1 DP)?
Transcribed Image Text:A gazelle is grazing under a tree. At time t 0 seconds, a cheetah, 100 m to the left of the tree, sees the gazelle and begins a chase. The following is a graph of the velocity of the cheetah's pursuit: 60- 40- 20- 10 12 -20- -40- -60- The cheetah's velocity fits the equation: v(t) = 0.1(t + 1)(t- 8)(t - 20) = 0.1(t3 - 27t2 + 132t + 160) %3D where t is the time in seconds in the range 0 <t s 10. The cheetah captures the gazelle time t = 10 seconds. Assume the cheetah runs in a straight line. i) What distance did the cheetah run during the 10 second chase? ii) The graph shows the cheetah reached maximum velocity at some time between time t=2 and t=D4 seconds. At what time exactly did the cheetah reach this maximum velocity (to 1 DP)?
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