A gaseous reaction occurs according to the two-step mechanism shown below. Step 1: AX +Y2 ⇄ AXY2 (fast) Step 2: AXY2 + AX → 2 AXY (slow) What is the rate law of the reaction? rate = k[AXY]2 [AXY2]-1[AX]-1 rate = k[AX]2[Y2] rate = k[AX][AXY2] rate = k[AX] rate = k[AX] [Y2]2
A gaseous reaction occurs according to the two-step mechanism shown below. Step 1: AX +Y2 ⇄ AXY2 (fast) Step 2: AXY2 + AX → 2 AXY (slow) What is the rate law of the reaction? rate = k[AXY]2 [AXY2]-1[AX]-1 rate = k[AX]2[Y2] rate = k[AX][AXY2] rate = k[AX] rate = k[AX] [Y2]2
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A gaseous reaction occurs according to the two-step mechanism shown below.
Step 1: AX +Y2 ⇄ AXY2 (fast)
Step 2: AXY2 + AX → 2 AXY (slow)
What is the rate law of the reaction?
rate = k[AXY]2 [AXY2]-1[AX]-1
rate = k[AX]2[Y2]
rate = k[AX][AXY2]
rate = k[AX]
rate = k[AX] [Y2]2
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