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A gas is taken through the cyclic process described in the figure. (The x axis is marked in increments of 5 m³.) P (kPa) 8 6 4 2 A A -V (m³)

A gas is taken through the cyclic process described in the figure. (The x axis is marked in increments of 5 m³.) P (kPa) 8 6 4 2 A A -V (m³)

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Any help would be very helpful for part a and part b as I can’t seem to get the correct answers. If I could get a good breakdown of everything to show why and how that would be extremely helpful. To show how the answer was achieved
A gas is taken through the cyclic process described the figure. (The x axis is marked in increments of 5 m³.) P (kPa) 8 6 4 2 A B C -V (m³) (a) Find the net energy transferred to the system by heat during one complete cycle. KJ (b) If the cycle is reversed-that is, the process follows the path ACBA-what is the net energy input per cycle by heat? kJ
Transcribed Image Text:A gas is taken through the cyclic process described the figure. (The x axis is marked in increments of 5 m³.) P (kPa) 8 6 4 2 A B C -V (m³) (a) Find the net energy transferred to the system by heat during one complete cycle. KJ (b) If the cycle is reversed-that is, the process follows the path ACBA-what is the net energy input per cycle by heat? kJ
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Step 1

(a) The net energy transferred to the system by heat during a complete cycle

The x-axis is marked in increments of 5 m3. The value of A on volume axis is 5 m3, in the middle is 10 m3 and the value of B on volume axis is 15 m3

In the P-V diagram, the work done by this process is equal to the area under the curve. 

The area ABC is a triangle. So the area of this triangle is 

W=12×AC×BC

The value of AC is 15 m3-5 m3=10 m3

The value of BC is 8 kPa-2 kPa=6 kPa. 

Note: kPa=1000 Pa, so 6 kPa is equal to 6000 Pa 

 

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