A gas follows the equation state: p=RT/V_m - a/(V_m^2 ) and the strength of intermolecular interaction a > 0. Answer the following questions. (a) Derive the expression (∂p/(∂V_m ) )_T in terms of R, T, a, and/or Vm. (b) Derive the expression (∂p/∂T )_(V_m ) in terms of R, T, a, and/or Vm. (c) Which of the above partial derivatives ((∂p/(∂V_m ) )_T and (∂p/∂T )_(V_m )) CANNOT have a negative value? Note that temperature is in Kelvin scale, and temperate cannot go below 0 K.
A gas follows the equation state: p=RT/V_m - a/(V_m^2 ) and the strength of intermolecular interaction a > 0. Answer the following questions. (a) Derive the expression (∂p/(∂V_m ) )_T in terms of R, T, a, and/or Vm. (b) Derive the expression (∂p/∂T )_(V_m ) in terms of R, T, a, and/or Vm. (c) Which of the above partial derivatives ((∂p/(∂V_m ) )_T and (∂p/∂T )_(V_m )) CANNOT have a negative value? Note that temperature is in Kelvin scale, and temperate cannot go below 0 K.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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- A gas follows the equation state: p=RT/V_m - a/(V_m^2 ) and the strength of intermolecular interaction a > 0. Answer the following questions.
(a) Derive the expression (∂p/(∂V_m ) )_T in terms of R, T, a, and/or Vm.
(b) Derive the expression (∂p/∂T )_(V_m ) in terms of R, T, a, and/or Vm.
(c) Which of the above partial derivatives ((∂p/(∂V_m ) )_T and (∂p/∂T )_(V_m )) CANNOT have a negative value? Note that temperature is in Kelvin scale, and temperate cannot go below 0 K.
(d) Can the pressure p in the above equation of state be a state function? Namely, is the total differential dpexact? Show your detailed derivation.
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