A furniture carrier pushes a 60 kg crate with a constant velocity v = 2.0 m/s on a rough inclined plane with a height of 1.0 m and a length of 2.0 m with a coefficient of kinetic friction uk = 0.30. What is the amount of change in potential energy of the crate? %3D
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- A force, in an angle of 32º, is applied to a 28-kg object which caused it to accelerate at 12 m/s2. It moved at a distance of 34 m, horizontally. How much work is done by the force? a. 9688.10 J b. 0 J c. 6053.80 J d. 4528.57 JSolve it correctly please. IA 11 g particle is moving to the left at 17 m/s. How much net work must be done on the particle to cause it to move to the right at 45 m/s ? Express your answer to two significant figures and include the appropriate units. µA ? W = Value Units Submit Request Answer Provide Feedback Next >
- I want the correct answer with explanation"30 kg bear slides, from rest, 12 m down a Lodgepole Pine tree, moving with a speed of 5.6 m/s just before hitting the ground. What change occurs in the gravitational potential energy of the bear Earth system during the slide?" O 3528 J O -2250 J O -3330 J O Data is not enough to calculate potential energy changeA. Calculate the work done by the force of gravity when a 5.0kg object is lifted to a height of 30.0m above the ground B. Calculate the velocity with which the object strikes the ground if dropped from that height, using the principle of conservation of energy C. Calculate the kinetic energy and the potential energy of the object at a halfway on the path after it is dropped. To do this part, you need to find the velocity of the object at that position using an equation of motion. What is the total energy of the object at that point? Does this verify the principle of conservation of energy?
- A force FY shown in the figure below acts on a particle moving along the y axis. Each unit in the y(m) axis is equal to 2.0m and each unit in the Fy (N) axis is equal to 3.0N. Determine the work done on the particle by this force as it moves from the following initial to final positions. A. From y=A to y=B B. From y=B to y=C C. From y=A to y=C.A 2 kg block is placed at rest on a frictionless incline that is angled 25 degrees. It is released and slides 30.0 cm (distance s) along the incline before reaching the floor. The floor exerts a kinetic friction force, F, of 1 N on the block. a. What is the total work done on the block? b. How far does the block slide (distance x) on the flat section of the floor (different from s) before it stops?QUESTION 16 A crate of mass, m, slides down a plane inclined at an angle, 0, to the horizontal for a distance x down the incline. If the coefficient of kinetic friction between the inclined surface and the crate is µk. what is the work done by friction? a. -Hkmgxcose b. -mgxcose C. -mgxcose/µk d. -µkmgxtane e. -mgxsin0
- An object with a mass of 15kg slides down an incline with a length of 6.0m at an angle of 28 degrees from horizontal. The coefficient of friction between the object and incline is 0.25 a) How much work does the gravitational force perform on the object? b) How much work does the frictional force perform on the object? c) What will its speed be as it reaches the bottom of the incline?A bag of wheat weight 130 kg. To what height should it be raised so that potential energy is 150 J? Take g = 9.8 m/s? %3D