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A fully discharged capacitor is connected in series to a resistor and a battery of constant voltage. The capacitor gets fully charged in a time of approximately 30 seconds. Which of the following changes would make the capacitor become fully charged in less time? Add a second resistor in series to the first one O Add a second resistor in parallel to the first one O Increase the voltage of the battery Decrease the voltage of the battery

A fully discharged capacitor is connected in series to a resistor and a battery of constant voltage. The capacitor gets fully charged in a time of approximately 30 seconds. Which of the following changes would make the capacitor become fully charged in less time? Add a second resistor in series to the first one O Add a second resistor in parallel to the first one O Increase the voltage of the battery Decrease the voltage of the battery

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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### Problem Statement A fully discharged capacitor is connected in series to a resistor and a battery of constant voltage. The capacitor gets fully charged in a time of approximately 30 seconds. Which of the following changes would make the capacitor become fully charged in less time? 1. Add a second resistor in series to the first one 2. Add a second resistor in parallel to the first one 3. Increase the voltage of the battery 4. Decrease the voltage of the battery ### Explanation In the context of charging a capacitor in a resistor-capacitor (RC) circuit: - **Increasing the voltage of the battery** would typically reduce the charging time because the higher voltage provides more potential difference to charge the capacitor faster. - **Adding a second resistor in series** will increase the total resistance, which usually increases the charging time. - **Adding a second resistor in parallel** to the first one decreases the total resistance, thus reducing the charging time. - **Decreasing the voltage of the battery** would increase the charging time due to the reduced potential difference. Therefore, options such as increasing the battery voltage or decreasing the resistance (by adding a parallel resistor) can effectively shorten the charging time.
Transcribed Image Text:### Problem Statement A fully discharged capacitor is connected in series to a resistor and a battery of constant voltage. The capacitor gets fully charged in a time of approximately 30 seconds. Which of the following changes would make the capacitor become fully charged in less time? 1. Add a second resistor in series to the first one 2. Add a second resistor in parallel to the first one 3. Increase the voltage of the battery 4. Decrease the voltage of the battery ### Explanation In the context of charging a capacitor in a resistor-capacitor (RC) circuit: - **Increasing the voltage of the battery** would typically reduce the charging time because the higher voltage provides more potential difference to charge the capacitor faster. - **Adding a second resistor in series** will increase the total resistance, which usually increases the charging time. - **Adding a second resistor in parallel** to the first one decreases the total resistance, thus reducing the charging time. - **Decreasing the voltage of the battery** would increase the charging time due to the reduced potential difference. Therefore, options such as increasing the battery voltage or decreasing the resistance (by adding a parallel resistor) can effectively shorten the charging time.
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