A fruit fly of height H sits in front of lens 1 on the central axis through the lens.The lens forms an image of the fly at a distance d = 21 cm from the fly; the image has the fly's orientation and height H = 2.4 H. What are (a) the focal length f of the lens and (b) the object distance p1 of the fly? The fly then leaves lens 1 and sits in front of lens 2, which also forms an image atd = 21 cm that has the same orientation as the fly, but now H = 0.76 H. What are (c) f2 and (d) P2?
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- I need Help please.Two lenses are separated by 50 cm. Lens 1 is convex and has a radius of curvature of magnitude 30 cm. Lens 2 is concave and has a radius of curvature of magnitude 40 cm and is located to the right of Lens 1. An object is located 20 cm to left of lens 1. Find the location of the final image of the object. What is the magnification of the final image?It is your first day at work as a summer intern at an optics company. Your supervisor hands you a diverging lens and asks you to measure its focal length. You know that with a converging lens, you can measure the focal length by placing an object a distance ss to the left of the lens, far enough from the lens for the image to be real, and viewing the image on a screen that is to the right of the lens. By adjusting the position of the screen until the image is in sharp focus, you can determine the image distance s′s′ and then use the equation 1s+1s′=1f1s+1s′=1f, to calculate the focal length ff of the lens. But this procedure won't work with a diverging lens−−by itself, a diverging lens produces only virtual images, which can't be projected onto a screen. Therefore, to determine the focal length of a diverging lens, you do the following: First you take a converging lens and measure that, for an object 20.0 cmcm to the left of the lens, the image is 29.7 cmcm to the right of the lens.…
- A system of two converging lenses forms an image of an arrow as shown. The first lens is located at x = 0 and has a focal length of f₁ = 8.8 cm. The second lens is located at x = x2 = 58.13 cm and has a focal length of f2 = 21 cm. The tip of the object arrow is located at (x,y) = (xo,Y)= (-12.3 cm, 6.9 cm). AY (X,Y) 1) What is x₁, the x-coordinate of image of the arrow formed by the first lens? cm Submit 2) What is y₁, the y-coordinate of the image of the tip of the arrow formed by the first lens? cm Submit Virtual and Inverted Virtual and Upright Submit X₂ cm Submit X 3) What is x3, the x co-ordinate of image of the arrow formed by the two lens system? cm Submit 5) What is the nature of the final image relative to the object? Real and Inverted Real and Upright ++++ 4) What is y3, the y-coordinate of the image of the tip of the arrow formed by the two lens system? + 6) Which of the following changes to the locations of the lenses would result in a virtual and inverted image of the…Is the final image real or virtual? Is the final image upright or inverted?You unconsciously estimate the distance to an object from the angle it subtends in your field of view. This angle 0 in radians is related to the linear height of the object h and to the distance d by 0= h/d. Assume that you are driving a car and that another car, 1.50 m high, is 22.0 m behind you. KTO & $3 m (d) What angle does the image subtend at your eyes? rad (e) Based on its angular size, how far away does the following car appear to be? m 0 1900 Per Works Inc OBJECTS IN MIRROR ARE CLOSER THAN THEY APPEAR vestest by Creators Syndicate The Far Side by Gary Larson 1985 FarWorks, Inc. All Rights Reserved. Used with permission. (a) Suppose your car has a flat passenger-side rearview mirror, 1.55 m from your eyes. How far from your eyes is the image of the car following you? m (b) What angle does the image subtend in your field of view? rad (c) Suppose instead your car has a convex rearview mirror (see figures) with a radius of curvature of magnitude 1.70 m. How far from your eyes is…
- For safety reasons, you install a rear-window lens with a -0.299 m focal length in your van. Before putting the van in reverse, you look through the lens and see the image of a person who appears to be 0.339 m tall and 0.243 m behind the van. Determine the following. (a) actual distance of the person behind the van m (b) height of the personThe lens-maker’s equation for a lens with index n1 immersed in a medium with index n2 takes the form A thin diverging glass (index = 1.50) lens with R1 = −3.00 m and R2 = −6.00 m is surrounded by air. An arrow is placed 10.0 m to the left of the lens. (a) Determine the position of the image. Repeat part (a) with the arrow and lens immersed in (b) water (index = 1.33) (c) a medium with an index of refraction of 2.00. (d) How can a lens that is diverging in air be changed into a converging lens?A farsighted person can read printing as close as 25.0 cm when she wears contacts that have a focal length of 38.0 cm. One day, however, she forgets her contacts and uses a magnifying glass, as in the drawing. It has a maximum angular magnification of 7.42 for a young person with a normal near point of 25.0 cm. What is the maximum angular magnification that the magnifying glass can provide for her? Virtual Magnifying glass Object LE ho dj. image