B4. Let X₁,... Xn ~ N(μ, o2) be independent random variables.2(a) From lectures we know (X=X) ²³.X₂(b) Letni=1~ x²(v). What is the value of v?n1*³ =, ²-₁, [(x₁ - x) ².Σ(xsn 1i=1Determine Var(s), that is, the variance of the sample variance.(c) Assume now that we have observed data ₁,...,n ER with sample variance s².Use the result from part (a) to find numbers an and b, such that [ans, bns] isan exact 95%-confidence interval for o².

Answered: Image /qna-images/answer/e583ec77-903a-4079-ae0e-805548e897ba.jpg

Answered: (a) From lectures we know (b) Let n…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A population has a mean µ = 161 and a standard deviation o = 20. Find the mean and standard deviation of the sampling distribution of sample means with sample size n = 56. The mean is = μx (Round to three decimal places as needed.) and the standard deviation is o- = X 3 X
Say you have two sets of data X1, ..., X10 and Y1,..., Y40. All of this data is considered independent. The first set of data are Normally distributed with mean B and variance 10. The second set of data are Normally distributed with mean y and variance 10. We are trying to estimate 0 = X = X; 18 + y. Consider the estimate ô = }X + Ÿ where 3 4 iX + Y where 10 vi=1 1 10 and Y = E Y;? 40 vi=1 40 (a) What is the mean, variance and distribution of 0? (b) What is the probability that 0 is larger than 1 away from 0? (c) What is the bias, variance and MSE of the estimate 0 for estimating 0?
What is the variance and standard deviation for the number of times the SAT is taken? x Frequency (f) fx f*x2= (f*x) x (x) (4) = (3)x(1) 5152727-(2547473)(2547473)/1518859=880035.3688/1518859=0.5794 (1) (2) (3)=(1)x(2) (4)=(3x1) Population Variance 1 721,769 721,769 721,769 2 601,325 1,202,650 2,405,300 3 166,736 500,208 1,500,624 4 22,299 89,196 356,784 5 6,730 33,650 168,250 Total 1,518,859 2,547,473 5,152,727 880035.3688 0.5794 n=1,518,859 ∑fx = 2,547,473 The population variance is 0.5794 The Standard Deviation? 0.76 Can you show me the steps to reach the standard deviation of .76 ?
Explain at least two differences between the following two point estimations of the population variance. 22 = Σ'1(X, – X)2 n-1 62 _ Σ 1 (X - X)2 =1 = n
i was wondering if i could get help with questions a and b
ou should complete the table as part of the procedure of finding the variance and standard deviation. Xi (Xi-(mu)) | (Xi-(mu)) | 49 53 60 60 62 63 64 69 73 87 [Note, this is the same set of data points used in problem 6. How does this compare to the standard deviation computed in problem 6? Why might this be smaller?]
Let S1^2 be the sampling variance for a random sample of twelve values (amount of mercury in the blood) and let S2^2 be the sampling variance for a random sample of ten values (amount of lead in the blood); samples from the same population were used. The population variance for mercury measurements is assumed to be twice the corresponding population variance for lead measurements. We will further assume that S1^2 is independent of S2^2. 1. Find a number b such that P [(S1^2/S2^2)<=b]=0.95 enter such a b to three decimal places b= 2. Consider the number b calculated above, find a number a such that P[a<=(S1^2/S2^2)<=b]=0.90 enter said a to three decimal places. a=
DCX Suppose that an airline quotes a flight time of 2 hours, 10 minutes between two cities. Furthermore, suppose that historical flight records indicate that the actual flight time between the two cities, x, is uniformly distributed between 2 hours and 2 hours, 20 minutes. Letting the time unit be one minute, (a) Calculate the mean flight time (x) and the standard deviation (ax) of the flight time. (Round your answers to 4 decimal places.) ux OX (b) Find the probability that the flight time will be within one standard deviation of the mean. (Round your answer to 5 decimal places.) P = 18 Fo MAR LO 5 li Ⓒ A WD Show
7

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