A friend drops a .625 kg ball from 2.2 meters above you. Determine the force that you have to exert on the ball to catch it.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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A friend drops a .625 kg ball from 2.2 meters above you. Determine the force that you have to exert on the ball to catch it. 

Expert Solution
Step 1: Calculation of potential energies which is necessary to calculate work done.

Given that, the mass of the ball is m=0.625kg. The height of dropping the ball is H= 2.2 m.

1.Calculate the initial potential energy of the ball: Potential Energy (PE) = mass (m) × gravitational acceleration (g) × height (h) PE = 0.625 kg × 9.81 m/s² × 2.2m 2.calculate the final potential energy of the ball (when it reaches your hand): The final height is essentially zero, as it's at the level of your hand. So, PE_final = 0

3.Use the work-energy principle, which states that the change in potential energy equals the work done by the force applied: Work (W) = PE_initial - PE_final

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