A frictionless Ski jump is designed such that at the bottom of the hill there is a short flat section. After the flat part, the slope continues to a ramp that raises 0.01m at a 9° angle relative to the horizon. The top of the ski jump is 376m high off the ground. Block A has a mass of 19kg and is released from the top of the slope so that it slides down and makes it perfectly elastic collision with block B of mass 8.74 kg. This causes block B to slide up the frictionless ramp and undergo projectile motion before landing a horizontal distance X metres away from the ramp. 1) What is the speed of block B aft

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A: 2)vf                  vf = 2*4.752+2 m/s                  vf = 2.

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A: m = 62 g = 0.062 kgv = 34 m/s

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A: first mass = m1second mass (m2) = 4 m1h = 2.5 m μk = 0.35stopping distance after collision = d

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A: SOlution: Given that m1 = 4x102 kg m2 = 2x103 kg v2 = 20 m/s

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Q: The figure shows an approximate plot of force magnitude F versus time t during the collision of a 62…

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A: The height of block 1 of mass m1 is h=2.4 m The mass of block 2 is m2=3m1 The coefficient of kinetic…