A free hydrogen atom after absorbing a photon of wavelength λa gets excited from state n = 1 to n = 4. Immediately after electron jumps to n = m state by emitting a photon of wavelength λe. Let change in momentum of atom due to the absorption and the emission are ΔPa and Δpe respectively. If λa/ λe = 1/5. Which of the following is correct a) m = 2 b) ΔPa/Pe = 1/2 c) λe = 418 nm d) Ratio of K.E. of electron in the state n = m to n = 1 is ¼.

icon
Related questions
Question

A free hydrogen atom after absorbing a photon of wavelength λa gets excited from state n = 1 to n = 4. Immediately after electron jumps to n = m state by emitting a photon of wavelength λe. Let change in momentum of atom due to the absorption and the emission are ΔPa and Δpe respectively. If λa/ λe = 1/5.

Which of the following is correct

 

a) m = 2

b) ΔPa/Pe = 1/2

c) λe = 418 nm

d) Ratio of K.E. of electron in the state n = m to n = 1 is ¼.

Expert Solution
steps

Step by step

Solved in 2 steps with 1 images

Blurred answer