A four story "intermediate reinforced concrete moment frames" supports seismic weights of 1400 kip on each floor and 500 kip on the roof. The natural (fundamental) period of this frame as T=0.6 sec. Based on ASCE 7-16 procedures, the base shear this frame must resist in an earthquake is V=846 kip
A four story "intermediate reinforced concrete moment frames" supports seismic weights of 1400 kip on each floor and 500 kip on the roof. The natural (fundamental) period of this frame as T=0.6 sec. Based on ASCE 7-16 procedures, the base shear this frame must resist in an earthquake is V=846 kip
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
![A four-story "intermediate reinforced concrete moment frame" supports seismic weights of 1400 kips on each floor and 500 kips on the roof. The natural (fundamental) period of this frame is \( T = 0.6 \) seconds. Based on ASCE 7-16 procedures, the base shear this frame must resist in an earthquake is \( V = 846 \) kips.
### Diagram Explanation:
- The diagram depicts a four-story structure with equal floor heights of 14 feet.
- Each floor (from bottom to top) supports seismic weights of 1400 kips, except the roof, which supports 500 kips.
- The structure is modeled as a moment frame with a uniform grid representing beams and columns.
### Instructions:
1. **Natural Period Interpolation:**
- Linearly interpolate the value of \( k \) suitable for the equivalent lateral force method based on the natural period.
2. **Vertical Distribution Calculation:**
- Use the interpolated \( k \) value and the given base shear to compute the vertical distribution of lateral loads.
3. **Elevation Drawing with Lateral Loads:**
- Illustrate an elevation of the frame, marking lateral loads on each floor and the roof.
4. **Vertical Distribution with \( k = 2 \):**
- Assume \( k = 2 \) and compute the vertical distribution of the lateral loads.
5. **Elevation Drawing with \( k = 2 \):**
- Create an elevation drawing showcasing the lateral loads on each floor and the roof based on \( k = 2 \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1420db0a-b432-4e35-a393-1b1ae00a8fe8%2Ff51d0362-9940-40b7-a909-ed6d8484c2ba%2Fz15zllm_processed.png&w=3840&q=75)
Transcribed Image Text:A four-story "intermediate reinforced concrete moment frame" supports seismic weights of 1400 kips on each floor and 500 kips on the roof. The natural (fundamental) period of this frame is \( T = 0.6 \) seconds. Based on ASCE 7-16 procedures, the base shear this frame must resist in an earthquake is \( V = 846 \) kips.
### Diagram Explanation:
- The diagram depicts a four-story structure with equal floor heights of 14 feet.
- Each floor (from bottom to top) supports seismic weights of 1400 kips, except the roof, which supports 500 kips.
- The structure is modeled as a moment frame with a uniform grid representing beams and columns.
### Instructions:
1. **Natural Period Interpolation:**
- Linearly interpolate the value of \( k \) suitable for the equivalent lateral force method based on the natural period.
2. **Vertical Distribution Calculation:**
- Use the interpolated \( k \) value and the given base shear to compute the vertical distribution of lateral loads.
3. **Elevation Drawing with Lateral Loads:**
- Illustrate an elevation of the frame, marking lateral loads on each floor and the roof.
4. **Vertical Distribution with \( k = 2 \):**
- Assume \( k = 2 \) and compute the vertical distribution of the lateral loads.
5. **Elevation Drawing with \( k = 2 \):**
- Create an elevation drawing showcasing the lateral loads on each floor and the roof based on \( k = 2 \).
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VIEWStep 4: Plot vertical distribution of lateral loads
VIEWStep 5: Compute vertical distribution of lateral loads for k=2
VIEWStep 6: Plot vertical distribution of lateral loads for k=2
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