A four story "intermediate reinforced concrete moment frames" supports seismic weights of 1400 kip on each floor and 500 kip on the roof. The natural (fundamental) period of this frame as T=0.6 sec. Based on ASCE 7-16 procedures, the base shear this frame must resist in an earthquake is V=846 kip

Structural Analysis
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Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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A four-story "intermediate reinforced concrete moment frame" supports seismic weights of 1400 kips on each floor and 500 kips on the roof. The natural (fundamental) period of this frame is \( T = 0.6 \) seconds. Based on ASCE 7-16 procedures, the base shear this frame must resist in an earthquake is \( V = 846 \) kips.

### Diagram Explanation:
- The diagram depicts a four-story structure with equal floor heights of 14 feet.
- Each floor (from bottom to top) supports seismic weights of 1400 kips, except the roof, which supports 500 kips.
- The structure is modeled as a moment frame with a uniform grid representing beams and columns.

### Instructions:
1. **Natural Period Interpolation:**
   - Linearly interpolate the value of \( k \) suitable for the equivalent lateral force method based on the natural period.

2. **Vertical Distribution Calculation:**
   - Use the interpolated \( k \) value and the given base shear to compute the vertical distribution of lateral loads.

3. **Elevation Drawing with Lateral Loads:**
   - Illustrate an elevation of the frame, marking lateral loads on each floor and the roof.

4. **Vertical Distribution with \( k = 2 \):**
   - Assume \( k = 2 \) and compute the vertical distribution of the lateral loads.

5. **Elevation Drawing with \( k = 2 \):**
   - Create an elevation drawing showcasing the lateral loads on each floor and the roof based on \( k = 2 \).
Transcribed Image Text:A four-story "intermediate reinforced concrete moment frame" supports seismic weights of 1400 kips on each floor and 500 kips on the roof. The natural (fundamental) period of this frame is \( T = 0.6 \) seconds. Based on ASCE 7-16 procedures, the base shear this frame must resist in an earthquake is \( V = 846 \) kips. ### Diagram Explanation: - The diagram depicts a four-story structure with equal floor heights of 14 feet. - Each floor (from bottom to top) supports seismic weights of 1400 kips, except the roof, which supports 500 kips. - The structure is modeled as a moment frame with a uniform grid representing beams and columns. ### Instructions: 1. **Natural Period Interpolation:** - Linearly interpolate the value of \( k \) suitable for the equivalent lateral force method based on the natural period. 2. **Vertical Distribution Calculation:** - Use the interpolated \( k \) value and the given base shear to compute the vertical distribution of lateral loads. 3. **Elevation Drawing with Lateral Loads:** - Illustrate an elevation of the frame, marking lateral loads on each floor and the roof. 4. **Vertical Distribution with \( k = 2 \):** - Assume \( k = 2 \) and compute the vertical distribution of the lateral loads. 5. **Elevation Drawing with \( k = 2 \):** - Create an elevation drawing showcasing the lateral loads on each floor and the roof based on \( k = 2 \).
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