force of magnitude 25.0 N acting at a 60.0° angle to the horizontal pulls a block 5.00 m along the floor. a) Find the work done on the box: W = ? JoulesNow consider if the box experiences a frictional force F, = 5.00 N. b) If the box moved 5.00 m, find the net work done on the box: W =? Joules **Problem: Analyzing Work Done on a Block with Forces Acting at an Angle**A force of magnitude 25.0 N acting at a 60.0° angle to the horizontal pulls a block 5.00 m along the floor.**a) Calculate the Work Done on the Box:**The work done, \( W \), when a force is applied is calculated as:\[ W = F \cdot d \cdot \cos(\theta) \]Where:- \( F = 25.0 \, \text{N} \) is the magnitude of the force.- \( d = 5.00 \, \text{m} \) is the distance.- \( \theta = 60.0^\circ \) is the angle of the force to the horizontal.Using this formula, the work done on the box is calculated to be:\[ W = 62.5 \, \text{Joules} \]**Diagrams:**1. The diagram shows a block with a force vector \( F_{\text{applied}} = 25.0 \, \text{N} \) at a 60.0° angle to the horizontal. It also shows components \( F_N \) (normal force) and \( F_g \) (gravitational force) vertically.**b) Consider the Box Experiences a Frictional Force \( F_f = 5.00 \, \text{N} \):**If the box moved 5.00 m, find the net work done on the box:The net work done account for the frictional force is calculated as:\[ W_{\text{net}} = F_{\text{applied}} \cdot d \cdot \cos(\theta) - F_f \cdot d \]Where:- \( F_f = 5.00 \, \text{N} \) is the frictional force.The result for the net work done is:\[ W_{\text{net}} = 20 \, \text{Joules} \]**Diagrams:**2. This diagram includes the horizontal frictional force \( F_{\text{friction}} = 5.00 \, \text{N} \) opposing the motion along with all previously mentioned forces and angles.These diagrams help in visualizing the forces acting on the block and their directions to calculate the

Name: force of magnitude 25.0 N acting at a 60.0° angle to the horizontal pu
Uploaded: 2024-03-20T06:57:25.000Z
Channel: Bartleby
Description: force of magnitude 25.0 N acting at a 60.0° angle to the horizontal pulls a block 5.00 m along the floor. a) Find the work done on the box: W = ? JoulesNow consider if the box experiences a frictional force F, = 5.00 N. b) If the box moved 5.00 m, f