17a-please help with part D only A force of constant magnitude pushes a box up a vertical surface, as shown in the figure.FThe box moves at a constant speed. If the mass of the box is 6.3 kg, it is pushed 2.9 m vertically upward, the coefficient of friction is 0.35, and the angle e is 30.0°, determine thefollowing.(a) the work done (in J) on the box by F(b) the work done (in J) on the box by the force of gravity(c) the work done (in J) on the box by the normal force(d) the increase in gravitational potential energy (in J) of the system of the box and earth as the box moves up the wall

Name: 17a-please help with part D only A force of constant magnitude pushes
Uploaded: 2024-03-05T11:56:34.000Z
Channel: Bartleby
Description: 17a-please help with part D only A force of constant magnitude pushes a box up a vertical surface, as shown in the figure.FThe box moves at a constant speed. If the mass of the box is 6.3 kg, it is pushed 2.9 m vertically upward, the coefficient of f

The change in gravitational potential energy is calculated by using the formula ∆EP=mg∆h ,where m=6.3 kg is the mass of the box ,g=9.8 m/s2 is the acceleration due to gravity and ∆h=2.9 m is the vertical height .Calculate the increase in potential energy by using the formula ∆EP=mg∆h ,where m=6.3 kg is the mass of the box ,g=9.8 m/s2 is the acceleration due to gravity and ∆h=2.9 m is the vertical height . ∆EP=mg∆h=6.3 kg×9.8 m/s2×2.9 m≈179 Jd) Thus the change in potential energy is ∆EP≈179 J .