A force Fj is applied to a mass M1. If the same force F1 is applied to a mass M2 = 4M¡ the acceleration of mass M, is: one-half the acceleration of the mass M. twice the acceleration of the mass Mɔ. the same as for the mass Mɔ. four times the acceleration of the mass M2. one-fourth the acceleration of the mass M2.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Physics Problem: Acceleration Comparison**

*A force \( F_1 \) is applied to a mass \( M_1 \). If the same force \( F_1 \) is applied to a mass \( M_2 = 4M_1 \), the acceleration of mass \( M_1 \) is:*

- ○ one-half the acceleration of the mass \( M_2 \).
- ○ twice the acceleration of the mass \( M_2 \).
- ○ the same as for the mass \( M_2 \).
- ○ four times the acceleration of the mass \( M_2 \).
- ○ one-fourth the acceleration of the mass \( M_2 \).

**Explanation:**

This problem requires understanding how acceleration is affected by mass when the same force is applied. According to Newton's second law, \( F = ma \), the acceleration (\( a \)) is inversely proportional to the mass (\( m \)) if the force (\( F \)) is constant. 

For mass \( M_2 = 4M_1 \), its acceleration will be \( \frac{1}{4} \) of that of \( M_1 \). Thus, the acceleration of mass \( M_1 \) is four times that of mass \( M_2 \).
Transcribed Image Text:**Physics Problem: Acceleration Comparison** *A force \( F_1 \) is applied to a mass \( M_1 \). If the same force \( F_1 \) is applied to a mass \( M_2 = 4M_1 \), the acceleration of mass \( M_1 \) is:* - ○ one-half the acceleration of the mass \( M_2 \). - ○ twice the acceleration of the mass \( M_2 \). - ○ the same as for the mass \( M_2 \). - ○ four times the acceleration of the mass \( M_2 \). - ○ one-fourth the acceleration of the mass \( M_2 \). **Explanation:** This problem requires understanding how acceleration is affected by mass when the same force is applied. According to Newton's second law, \( F = ma \), the acceleration (\( a \)) is inversely proportional to the mass (\( m \)) if the force (\( F \)) is constant. For mass \( M_2 = 4M_1 \), its acceleration will be \( \frac{1}{4} \) of that of \( M_1 \). Thus, the acceleration of mass \( M_1 \) is four times that of mass \( M_2 \).
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