A force F= (10 + 0'50 x) acts on a particle in the x direction, where F is in newton and x in meter. Find the work done by this force during a displacement from x=0 to x = 2-0 m.

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A force F=(10 + 0'50 x) acts on a particle in the
x direction, where F is in newton and x in meter. Find
the work done by this force during a displacement from
x= 0 to x = 2.0 m.
Transcribed Image Text:A force F=(10 + 0'50 x) acts on a particle in the x direction, where F is in newton and x in meter. Find the work done by this force during a displacement from x= 0 to x = 2.0 m.
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