a) for (int count = 1; count < 100; count++); 66 66 cout << (10* count) b) int total 75,score=20; total + score: system.println("New Total is"); system.printf("%d,%n,%d%n%d", ++ total, total - - ,total); c) int i = 1; while (i <= 10) { { } if(i==8) break; cout<< i+ 3; itti d) int i,j; for(i=0;i<2;i++) for(j=0;j<=3;j++) { cout<< "Hi": } cout<<<'*'; }

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Below is the transcription of the code:

---

**Assume the code below is part of a complete program, what will be the output of the code?**

**a)**
```cpp
for (int count = 1; count < 100; count++);
cout << (10 * count) << “ “;
```
**[Output for section a will be:]**
```
1000
```

**b)**
```cpp
int total=75, score=20;
total += score;
system.println(“New Total is”);
system.printf(“%d,%d,%d%n%d”, ++total, total – –,total);
```
**[Output for section b will be:]**
```
New Total is
96,96,95
```

**c)**
```cpp
int j = 1;
while (j <= 10)
{
    if(j==8)
        break;
    cout<< i+ 3;
    i++;
}
```
**[Output for section c will be:]**
```
4 5 6 7 8 9 10
```

**d)**
```cpp
int i,j;
for(i=0;i<2;i++)
{
    for(j=0;j<=3;j++)
    {
        cout<< “Hi”;
    }
    cout<<“*”;
}
```
**[Output for section d will be:]**
```
HiHiHiHi*HiHiHiHi*
```

---

**Explanation of Code Sections:**

**Section a** uses a `for` loop that iterates from 1 to less than 100. After the loop completes, it prints `10 * count`, which results in `1000`.

**Section b** initializes `total` and `score`, incrementing `total` by `score`. It prints a formatted string using `system.println` and `system.printf`.

**Section c** has a `while` loop from 1 to 10, breaking out when `j` equals 8, and prints incremented values.

**Section d** contains nested `for` loops, inner loop prints “Hi” 4 times followed by “*”, repeating this sequence twice.

Note: The usage of `system.println` and `system.printf` seems incorrect and should be corrected to standard output methods in the actual implementation (e.g., `System.out.println` for Java or `printf` for
Transcribed Image Text:Below is the transcription of the code: --- **Assume the code below is part of a complete program, what will be the output of the code?** **a)** ```cpp for (int count = 1; count < 100; count++); cout << (10 * count) << “ “; ``` **[Output for section a will be:]** ``` 1000 ``` **b)** ```cpp int total=75, score=20; total += score; system.println(“New Total is”); system.printf(“%d,%d,%d%n%d”, ++total, total – –,total); ``` **[Output for section b will be:]** ``` New Total is 96,96,95 ``` **c)** ```cpp int j = 1; while (j <= 10) { if(j==8) break; cout<< i+ 3; i++; } ``` **[Output for section c will be:]** ``` 4 5 6 7 8 9 10 ``` **d)** ```cpp int i,j; for(i=0;i<2;i++) { for(j=0;j<=3;j++) { cout<< “Hi”; } cout<<“*”; } ``` **[Output for section d will be:]** ``` HiHiHiHi*HiHiHiHi* ``` --- **Explanation of Code Sections:** **Section a** uses a `for` loop that iterates from 1 to less than 100. After the loop completes, it prints `10 * count`, which results in `1000`. **Section b** initializes `total` and `score`, incrementing `total` by `score`. It prints a formatted string using `system.println` and `system.printf`. **Section c** has a `while` loop from 1 to 10, breaking out when `j` equals 8, and prints incremented values. **Section d** contains nested `for` loops, inner loop prints “Hi” 4 times followed by “*”, repeating this sequence twice. Note: The usage of `system.println` and `system.printf` seems incorrect and should be corrected to standard output methods in the actual implementation (e.g., `System.out.println` for Java or `printf` for
Expert Solution
Step 1 The above given programs are in Java & C++ and requires simple output.

1. In this question the for loop is given with initializing variable name count and conditions are given  , the output is - 

//Question Number 1

#include <iostream>

using namespace std;

//Main function

int main() {

//for loop with count variable initialized with 1 

//loop has condition count smaller than 100 , so loop will run 99 times 

for(int count = 1; count <100;count++){

//every time loop will run it will print the value of count multiply by 10 and space 

    cout<<(10*count)<<" ";

}

    return 0;

}

OUTPUT:- 

Computer Science homework question answer, step 1, image 1

 

 

Count has initial value of 1 and condition is count smaller than 100 (so its 99). So loop will run 99 times and every time loop runs it will print the value of count multiply by 10 and space.

 

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