### Physics Problem: Projectile Motion#### Problem Statement:A football is kicked at ground level with a speed of 17.2 m/s at an angle of 30.2° to the horizontal.**Question:** How much later does it hit the ground?#### Diagram:The diagram shows a right triangle that illustrates the components of the football's initial velocity (V).- The hypotenuse represents the initial velocity (17.2 m/s).- One side represents the horizontal velocity component (\(V_x\)).- The other side represents the vertical velocity component (\(V_y\)).- The angle between the hypotenuse and the horizontal side is 30.2°.- There is a point labeled as the ground and the direction of the projectile motion.The components can be calculated as follows:- \(V_x = V \cdot \cos(\theta)\)- \(V_y = V \cdot \sin(\theta)\)where \(V = 17.2 \, \text{m/s}\) and \(\theta = 30.2^\circ\).#### Equations and Calculation:1. Calculate horizontal and vertical components of the velocity: - \(V_x = 17.2 \, \text{m/s} \cdot \cos(30.2^\circ)\) - \(V_y = 17.2 \, \text{m/s} \cdot \sin(30.2^\circ)\)2. Using the vertical motion equations to find the time \(t\) it takes for the football to hit the ground:Since \(\Delta y = 0\) (the football starts and ends at ground level):\[ \Delta y = V_y \cdot t - \frac{1}{2} g t^2 \]Given:- \(g = 9.81 \, \text{m/s}^2\)- \( \Delta y = 0 \)\[ 0 = (17.2 \cdot \sin(30.2^\circ)) t - \frac{1}{2} \cdot 9.81 \cdot t^2 \]This can be solved for \(t\):\[ t = \frac{2 \cdot (17.2 \cdot \sin(30.2^\circ))}{9.81} \]Solve this equation to find the time \(t

Name: ### Physics Problem: Projectile Motion#### Problem Statement:A footba
Uploaded: 2024-03-20T06:57:47.000Z
Channel: Bartleby
Description: ### Physics Problem: Projectile Motion#### Problem Statement:A football is kicked at ground level with a speed of 17.2 m/s at an angle of 30.2° to the horizontal.**Question:** How much later does it hit the ground?#### Diagram:The diagram shows a ri