A football is kicked at 25.0 m/s at an angle of 31.0° above the horizontal. Assume it starts 1.00 m above ground level. (Neglect any effects due to air resistance.) Describe the velocity vector of the ball in terms of its x- and y-components, Ux and Uy, respectively, when it is 6.00 m above ground level and still moving upward. m/s Uy = m/s Describe the velocity vector of the ball in terms of its magnitude v and angle 0 above the horizon when it is 6.00 m above ground level and still moving upward. V= m/s 0 =

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Chapter1: Units, Trigonometry. And Vectors
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A football is kicked at 25.0 m/s at an angle of 31.0° above the horizontal. Assume it starts 1.00 m above ground level. (Neglect
any effects due to air resistance.)
Describe the velocity vector of the ball in terms of its x- and y-components, Ux and Uy, respectively, when it is 6.00 m above
ground level and still moving upward.
m/s Uy =
m/s
Describe the velocity vector of the ball in terms of its magnitude v and angle 0 above the horizon when it is 6.00 m above ground
level and still moving upward.
V=
m/s
0 =
Transcribed Image Text:A football is kicked at 25.0 m/s at an angle of 31.0° above the horizontal. Assume it starts 1.00 m above ground level. (Neglect any effects due to air resistance.) Describe the velocity vector of the ball in terms of its x- and y-components, Ux and Uy, respectively, when it is 6.00 m above ground level and still moving upward. m/s Uy = m/s Describe the velocity vector of the ball in terms of its magnitude v and angle 0 above the horizon when it is 6.00 m above ground level and still moving upward. V= m/s 0 =
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