A food safety guideline is that the mercury in fish should be below 1 part per million (ppm). Listed below are the amounts of mercury (ppm) found in tuna sushi sampled at different stores in a major city. Construct a 99% confidence interval estimate of the mean amount of mercury in the population. Does it appear that there is toomuch mercury in tuna sushi?0.56 0.68 0.10 0.97 1.29 0.55 0.95 -What is the confidence interval estimate of the population mean p?O ppm

Name: A food safety guideline is that the mercury in fish should be below 1
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Description: A food safety guideline is that the mercury in fish should be below 1 part per million (ppm). Listed below are the amounts of mercury (ppm) found in tuna sushi sampled at different stores in a major city. Construct a 99% confidence interval estimate

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A food safety guideline is that the mercury in fish should be below 1 part per million (ppm). Listed below are the amounts of mercury (ppm) found in tuna sushi sampled at different stores in a major city. Construct a 99% confidence interval estimate of the mean amount of mercury in the population. Does it appear that there is too
much mercury in tuna sushi?
0.56 0.68 0.10 0.97 1.29 0.55 0.95 -
What is the confidence interval estimate of the population mean p?
O ppm <u<O ppm
(Round to three decimal places as needed.)
Does it appear that there is too much mercury in tuna sushi?
OA. Yes, because it is possible that the mean is not greater than 1 ppm. Also, at least one of the sample values exceeds 1 ppm, so at least some of the fish have too much mercury.
O B. No. because it is not possible that the mean is greater than 1 ppm. Also, at least one of the sample values is less than 1 ppm, so at least some of the fish are safe.
OC. Yes, because it is possible that the mean is greater than 1 ppm. Also, at least ane of the sample values exceeds 1 ppm, so at least some of the fish have too much marcury
OD. No, because it is possible that the mean is not greater than 1 ppm. Also, at least one of the sample values is less than 1 ppm, so at least some of the fish are safe.

Expert Solution

Step 1

Given :

sample : 0.56, 0.68, 0.10, 0.97, 1.29, 0.55, 0.95

sample size, n = 7

$α = 0.99$

$\bar{x} = \frac{\sum_{} X_{i}}{n}$

$\bar{x} = \frac{0.56 + . . . + 0.95}{7}$

$\bar{x} = \frac{5.1}{7}$

$\bar{x} = 0.7286$

$S a m p l e S \tan d a r d d e v i a t i o n, s = \sqrt{\frac{\sum_{} {(X_{i} - \bar{X})}^{2}}{n - 1}}$

$S a m p l e S \tan d a r d d e v i a t i o n, s = \sqrt{\frac{{(- 0.1686)}^{2} + . . . + {(0.2214)}^{2}}{7 - 1}}$

$S a m p l e S \tan d a r d d e v i a t i o n, s = \sqrt{\frac{0.8803}{6}}$

$S a m p l e S \tan d a r d d e v i a t i o n, s = 0.3830$

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