A food product containing 80% moisture content is being frozen. Estimate the specific heat of the product at -6°C when 82% of the water is frozen. The specific heat of the dry product is 2.5 kJ/(kg°C). It is assumed that the specific heat of water at -10°C is the same as the specific heat of water at 0°C, and that the specific heat of ice follows the function Cp es = 0.0062 Tbeku + 2.0649. identify : a. Cp frozen product = Answer in kJ/kg°C
A food product containing 80% moisture content is being frozen. Estimate the specific heat of the product at -6°C when 82% of the water is frozen. The specific heat of the dry product is 2.5 kJ/(kg°C). It is assumed that the specific heat of water at -10°C is the same as the specific heat of water at 0°C, and that the specific heat of ice follows the function Cp es = 0.0062 Tbeku + 2.0649. identify : a. Cp frozen product = Answer in kJ/kg°C
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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A food product containing 80% moisture content is being frozen. Estimate the specific heat of the product at -6°C when 82% of the water is frozen. The specific heat of the dry product is 2.5 kJ/(kg°C). It is assumed that the specific heat of water at -10°C is the same as the specific heat of water at 0°C, and that the specific heat of ice follows the function Cp es = 0.0062 Tbeku + 2.0649. identify :
a. Cp frozen product = Answer in kJ/kg°C
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