Answer it asap with full explanation if you are not give then i will downvote you A food company testing a new method for the analysis of thepolyunsaturated fat content of various vegetable and animaloils obtained the results in the table for the old andnew methods.Use a paired Student's t-test to determine if the new and oldanalysis procedures are giving the same results at the 95%confidence level. You can assume that the precision isapproximately the same for these two methods.Critical t values at various confidence intervals and degreesof freedom can be found in the Student's t table.*calculated=• no3.56Are the results the same at the 95% confidence level?yesIncorrectPolyunsaturated Fat(% w/w of total fat)Sample Old NewNumber Method Method14.5 3.9235.8 34.837.2 6.7466.2 63.3517.716.168.26.6747.144.2827.723.2tcritical =2.365

Given a food company testing a new method for analysis of polyunsaturated fat content of various…

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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For his thesis work, a masters student wanted to study the possible effects of newly discovered clotting agents on blood products when stored at certain temperatures. The data set on the right shows the results in minutes of the time it takes for blood to clot done in two trials over the course of the study period. Test the hypotheses that there is a difference among the variables at 95% confidence level using the p-value method. 1. Identify the independent variables = Clotting agent and Temperature2. Identify the dependent variable = The time taken for blood to clot.3. Identify the tail of the test. = two-tailed test4. Give the null hypothesis in words. = There is no significant difference in the blood clotting time between the variables clotting agent and temperature.5. Give the alternative hypothesis in words. = There is a significant difference in the blood clotting time between the variables clotting agent and temperature.6. Determine the critical value or p-value ().7. Identify…
A food company testing a new method for the analysis of the polyunsaturated fat content of various vegetable and animal oils obtained the results in the table for the old and new methods. Use a paired Student's r-test to determine if the new and old analysis procedures are giving the same results at the 95% confidence level. You can assume that the precision is approximately the same for these two methods. Critical 1 values at various confidence intervals and degrees of freedom can be found in the Student's / table. calculated= Are the results the same at the 95% confidence level? no yes Polyunsaturated Fat (% w/w of total fat) Sample Old New Number Method Method 1 5.3 4.8 2 35.8 34.6 3 4.5 4.2 4 66.3 63.3 5 19.6 18.1 6 7.9 6.3 7 48.3 45.6 8 28.6 24.1 feritical =
Employees were exposed to Compound X, one of the most toxic compounds, in a certain factory. There were20 employees tested initially. In order to assess their safety, the amounts of the compound levels in the plasma and in thefat tissue were studied and are shown below. In case that a significant difference between the two means was found, there is sufficient evidence that employees are atrisk of death and immediate measures and interventions should be done. Find a 95% confidence interval for the differenceof the true mean Compound X levels in the plasma and in the fat tissue, respectively. Assume the distribution of thedifferences to be approximately normal. What can you conclude about the difference in the mean Compound X levelsin the plasma and in the fat tissue of the employees? (Take note that if 0 is included in the interval, then there is nosignificant difference between the two parameters.)
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You may need to use the appropriate appendix table or technology to answer this question. The following results come from two independent random samples taken of two populations. Sample 1 Sample 2 n, = 50 n2 = 25 X = 13.6 X2 = 11.6 01 = 2.3 02 = 3 (a) What is the point estimate of the difference between the two population means? (Use x, - x.) 2.0 (b) Provide a 90% confidence interval for the difference between the two population means. (Use x, - x,. Round your answers to two decimal places.) 0.88 to 3.12 (c) Provide a 95% confidence interval for the difference between the two population means. (Use x, - x,. Round your answers to two decimal places.) 0.67 |x to 3.33
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It is believed that using a solid state drive (SSD) in a computer results in faster boot times when compared to a computer with a traditional hard disk (HDD). You sample a group of computers and use the sample statistics to calculate a 90% confidence interval of (-3.79, 6.59). This interval estimates the difference of (average boot time (HDD) - average boot time (SSD)). What can we conclude from this interval? Question 5 options: 1) We do not have enough information to make a conclusion. 2) We are 90% confident that the average boot time of all computers with an SSD is greater than the average of all computers with an HDD. 3) We are 90% confident that the difference between the two sample means falls within the interval. 4) We are 90% confident that the average boot time of all computers with an HDD is greater than the average of all computers with an SSD.…
In a study of morphological variation in natural populations of fruit fly, it was reported that the mean wing length of 16 females, collected in a certain area, was 4.653 mm with s = 0.012 mm; and the mean wing length of 11 females, collected in a second area, was 4.274 mm with s = 0.02. Let the distribution of the wing length be normal, find a 98% confidence interval on the ratio of the two populations’ standard deviations.

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