A fluoride ion-selective electrode has a selectivity coefficient Kot F, OH- = 0.1. What will be the change in electrode potential when the pH of 1.0 × 10-4 M solution of F is raised from pH = 5.5 to pH = 11.5. The potential of an ion-selective electrode is 0.05916 E= constant + B log([A]sample + EKAI:l1) where: z = -1 for fluoride ion and assume B = 1. Express your answer in units of Volt. Do not write down the unit.

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A fluoride ion-selective electrode has a selectivity coefficient \( k_{\text{F}^-, \text{OH}^-}^{\text{Pot}} = 0.1 \). What will be the change in electrode potential when the pH of a \( 1.0 \times 10^{-4} \) M solution of \( \text{F}^- \) is raised from pH = 5.5 to pH = 11.5?

The potential of an ion-selective electrode is

\[
E = \text{constant} + \beta \frac{0.05916}{z} \log\left([\text{A}]_{\text{sample}} + \sum_i k_{\text{A},i} \cdot [\text{I}]\right)
\]

where: \( z = -1 \) for fluoride ion and assume \( \beta = 1 \).

Express your answer in units of Volt. Do not write down the unit.
Transcribed Image Text:A fluoride ion-selective electrode has a selectivity coefficient \( k_{\text{F}^-, \text{OH}^-}^{\text{Pot}} = 0.1 \). What will be the change in electrode potential when the pH of a \( 1.0 \times 10^{-4} \) M solution of \( \text{F}^- \) is raised from pH = 5.5 to pH = 11.5? The potential of an ion-selective electrode is \[ E = \text{constant} + \beta \frac{0.05916}{z} \log\left([\text{A}]_{\text{sample}} + \sum_i k_{\text{A},i} \cdot [\text{I}]\right) \] where: \( z = -1 \) for fluoride ion and assume \( \beta = 1 \). Express your answer in units of Volt. Do not write down the unit.
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